Question

How many grams of o2 are required to produce 358.5 grams of zno??

Answer 1

Before you can identify how much you need, first you need to solve and write the equation.

You need to know first that you need to convert grams of ZnO --> moles of ZnO

= 358.5 g ZnO x 1 mol ZnO / 81.39g ZnO

Solve and it will give you = 4.40 mol of ZnO

Next, multiply the answer above to 1 mol O2 / 2 mol ZnO

It will give you the answer of 2.20 mol of O2

Multiply the answer above to the molar mass. This will give you the answer of what you’re looking for.

Molar mass: 32

= 2.20 mol O2 x 32g O2 / 1 mol O2

= 70.4g O2

The grams of O2 that are required to produce 385.5 grams of zno is: 70.4 g O2

Answer 2

Answer: 35.24 grams of $O_2$ are required to produce the given amount of Zinc oxide.

Explanation:

To calculate the number of moles, we use the formula:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

Given mass of zinc oxide = 358.5 g

Molar mass of zinc oxide = 81.38 g/mol

Putting values in above equation, we get:

$\text{Moles of zinc oxide}=\frac{358.5g}{81.38g/mol}=4.405mol$

For the reaction of formation of zinc oxide, the equation follows:

$2Zn+O_2\rightarrow 2ZnO$

By Stoichiometry of the reaction:

2 moles of zinc oxide is produced from 1 mole of oxygen gas

So, 4.405 moles of zinc oxide is produced from = $\frac{1}{2}\times 4.405mol=2.2025mol$ of oxygen.

Now, to calculate the mass of oxygen gas, we use equation 1:

Molar mass of oxygen gas = 16 g/mol

Moles of oxygen gas = 2.2025 mol

Putting values in equation 1, we get:

$2.2025mol=\frac{\text{Mass of oxygen}}{16g/mol}\\\\\text{Mass of oxygen}=35.24g$

Hence, 35.24 grams of $O_2$ are required to produce the given amount of Zinc oxide.