<u>Answer:</u> 35.24 grams of are required to produce the given amount of Zinc oxide.
<u>Explanation:</u>
To calculate the number of moles, we use the formula:
....(1)
Given mass of zinc oxide = 358.5 g
Molar mass of zinc oxide = 81.38 g/mol
Putting values in above equation, we get:
For the reaction of formation of zinc oxide, the equation follows:
By Stoichiometry of the reaction:
2 moles of zinc oxide is produced from 1 mole of oxygen gas
So, 4.405 moles of zinc oxide is produced from = of oxygen.
Now, to calculate the mass of oxygen gas, we use equation 1:
Molar mass of oxygen gas = 16 g/mol
Moles of oxygen gas = 2.2025 mol
Putting values in equation 1, we get:
Hence, 35.24 grams of are required to produce the given amount of Zinc oxide.