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2 years ago

Convert 0.54 km to dm

Chemistry

1 answer:

Kaylis [27]2 years ago

6 0

.54 km to dm is 5,400 decimeters. Hope this helps, have a BLESSED day! :-)

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Ill give brainlest to the one who answers right.

liraira [26]

The answer would be h2o

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2 years ago

Hi May I know what is the answer and how to get it

Trava [24]

Answer:

Explanation:

When lead ions and sulfate ions bond, they form sediment so neither a nor b can be the answer.

The important thing is that two nitrate ions were originally bonded with one lead ion, while two potassium ions bonded with a sulfate ion.

Finally, since potassium and nitrate ions don't form sediment these two ions must remain. Therefore the answer is D

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2 years ago

Mass is measured in= a. Liters b. centimeters c. newtons d. kilograms

ale4655 [162]

Mass is measured in kilograms.

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1 year ago

1. How much 6.0 M HNO3 is needed to neutralize 39 mL of 2.0 M KOH?

quester [9]

Answer:

For 2. the answer is 15.0 mL

For other examples, you can solve by exact way as I have solved the 2nd example.

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2 years ago

El agua del mar contiene aproximadamente un 3,0 % m/v de sal (NaCl, 58,44 g/mol), (asuma que es la única fuente de cloruros) si

Alchen [17]

Answer:

s = 4.41 g/L.

Explanation:

¡Hola!

En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:

$PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)$

Lo cual hace que la expresión de equilibrio se calcule como:

$Ksp=[Pb^{2+}][Cl^-]^2$

Y que en términos de la solubilidad molar, s, se resuelve como:

$1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L$

Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):

$s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L$

¡Saludos!

7 0

2 years ago