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Semenov [28]
3 years ago
11

Convert 0.54 km to dm

Chemistry
1 answer:
Kaylis [27]3 years ago
6 0

.54 km to dm is 5,400 decimeters. Hope this helps, have a BLESSED day! :-)

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Explain in terns of atomic structure why barium has a lower first ionization energy than magnesium.
Sonja [21]

Answer:

Barium has a greater radius than magnesium

Explanation:

Barium and magnesium are two elements which belong to the same group, group 2A. This means that the two elements have two valence electrons in their outer shell.

The difference is, however, since barium is lower in group than magnesium, it has more electron shells than magnesium and, therefore, its radius is greater. The attraction force between the nucleus and the valence electrons in barium is lower as a result, as force is inversely proportional to distance. Hence, a lower amount of energy is required to remove the valence electrons from barium.

3 0
3 years ago
Figure 1 shows a seaside cliff. Figure 2 shows the same cliff after a period of time has passed. What caused the change from fig
NeX [460]
The change from figure one to figure two was most likely caused by erosion. Erosion is the process of something being eroded by wind, water, or other natural agents.
7 0
2 years ago
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A radioactive isotope of potassium (K) has a half-life of 20 minutes. If a 40.0 gram sample of this isotope is allowed to decay
Ivahew [28]

Answer: 2.5 grams

Explanation:

5 0
3 years ago
Read 2 more answers
He wants to increase the energy of emitted electrons . Based on the research of Albert Einstein, what is the best way for him to
pishuonlain [190]

To increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.

<h3>What is energy of emitted electron?</h3>

The maximum energy of an emitted electron is equal to the energy of a photon for frequency f (E = hf ), minus the energy required to eject an electron from the metal's surface, also known as work function.

Ee = E - W

<h3>Energy of the emitted electron</h3>

The energy of emitted electrons based on the research of Albert Einstein is given as;

E = hf

where;

  • h is planck's constant
  • f is frequency of incident light on the metal

Thus, to increase the energy of the emitted electrons, the frequency of the incident light on the metal must be increased.

Learn more about energy of electron here: brainly.com/question/11316046

#SPJ1

8 0
1 year ago
Determine the kinetic energy of an 833.0 kg roller coaster car moving at a speed of 20.0 m/s
trasher [3.6K]

Answer:

166,600J

Explanation:

Kinetic energy (K.E), which is the energy due to motion of a body, can be calculated by using the formula;

K.E = 1/2 × m × v²

Where;

K.E = kinetic energy (joules)

m = mass of body (kg)

v = speed or velocity (m/s)

According to this question, the mass of the roller coaster is 833.0 kg while its velocity/speed is 20.0m/s.

K.E = 1/2 × 833 × 20²

K.E = 1/2 × 833 × 400

K.E = 1/2 × 333200

K.E = 166,600

Therefore, the kinetic energy of the roller coaster car is 166,600J.

6 0
2 years ago
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