The answer would be Alfred Wegener
Answer:
0.0847M is molarity of sodium hydrogen citrate in the solution
Explanation:
The 2.0%(w/v) solution of sodium hydrogen citrate contains 2g of the solute in 100mL of solution. To find the molarity of the solution we need to convert the mass of solute to moles using molar mass and the mL of solution to Liters because molarity is the ratio between moles of sodium hydrogen citrate and liters of solution.
<em>Moles Na2C6H6O7:</em>
<em>Molar Mass:</em>
2Na: 2*22.99g/mol: 45.98g/mol
6C: 6*12.01g/mol: 72.01g/mol
6H: 6*1.008g/mol: 6.048g/mol
7O: 7*16g/mol: 112g/mol
45.98g/mol + 72.01g/mol + 6.048g/mol + 112g/mol = 236.038g/mol
Moles of 2g:
2g * (1mol / 236.038g) = <em>8.473x10⁻³ moles</em>
<em />
<em>Liters solution:</em>
100mL * (1L / 1000mL) = <em>0.100L</em>
<em>Molarity:</em>
8.473x10⁻³ moles / 0.100L =
<h3>0.0847M is molarity of sodium hydrogen citrate in the solution</h3>
Step by step solution:
Its given;
Moles of neon at STP is 15 mol
We are required to calculate the volume;
According to molar gas volume, 1 mole of a gas occupies a volume of 22.4 liters at STP.
That is, 1 mole of a gas = 2.4 L
Therefore;
1 mole of Neon gas = 22.4 L
Volume = Moles of the gas × molar gas volume
= 15 mol × 22.4 L/mol
= 336 L
Calcium would be more reactive because it is closer to francium on the periodic table, francium is the MOST reactive element.