Answer is: the nature of the initial nickel sulfide mixture is a suspension.
Suspension<span> is a </span>heterogeneous mixture (solute<span> particles do not </span>dissolve), <span>that contains </span>solid<span> particles (in this example nickel sulfide or NiS) sufficiently large for </span>sedimentation. <span> The internal phase (solid nickel sulfide) is dispersed throughout the external phase (water).</span>
2Agl + 1Na2S----->1 Ag2S + 2Nal
This may help
After careful deliberation, I took the opportunity to find the answers for you.
Answers:
1) _2_Al + _6_HC2H3O2 ->_2_Al(C2H3O2)3 + _3_H2
3) _1_Fe + _2_HBr -> _1_H2 + _1_FeBr2
5) _2_NaOH + _1_ H2SO4 -> _1_Na2SO4 + _2_H2O
7) _2_N2O -> _2_N2 + _1_ O2
9) _1_P4O6 + _2_O2 -> _1_P4O10
11) _2_Mg + _2_CH3COOH -> _2_Mg(CH3COO)2 + _1_H2
13) _2_Al3 + _18_HCl -> _9_H2 + _6_AlCl3
15) _4_KOH + _2_H2SO4 -> _4_H2O + _2_K2SO4
17) _2_NH3 -> _1_N2 + _3_H2
19) _2_SO2 + _1_O2 -> _2_SO3
DONE! *breathes heavily* Alright, after like 30 minutes, these are the answers for your problem.
Hope this helps! :)
3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃
Explanation:
AgNO₃+Na₃(PO₄) → Ag₃(PO₄) + NaNO₃
To balance this chemical equation, we can adopt a simple mathematical approach through which we can establish simple and solvable algebraic equations.
aAgNO₃ + bNa₃PO₄ → cAg₃PO₄ + dNaNO₃
a, b, c and d are the coefficients needed to balance the equation.
Conserving Ag: a = 3c
N: a = d
O: 2a + 4b = 4c + 2d
Na: 3b = d
P: b = c
let a = 1; d = 1
b = 
c = 
Multiplying through by 3:
a = 3, b = 1, c = 1 and d = 3
3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃
Learn more:
Balanced equation
brainly.com/question/5964324
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