Answer:
Step-by-step explanation:
<u>Find the m∠B:</u>
- m∠B = (360° - 310°) + 50° = 100°
a)
<u>Find AC using law of cosines:</u>
- AC = √(8² + 13² - 28*13*cos 100°) = 16.4 km (rounded)
b)
<u>Find m∠A using law of sines:</u>
- 16.4/ sin 100 = 13 / sin A
- m∠A = arcsin (13 sin 100 deg / 16.4) = 51° (rounded)
<u>The bearing of C from A:</u>
c)
<u>Let the required distance is x:</u>
- x/ BC = sin 50°
- x = BC sin 50°
- x = 13 sin 50°
- x ≈ 10 km (rounded)
Interquartile range is the range is the number in the dead center, you have to divide the number line into 2 sections. The middle of everything and the middle of both section is the interquartile range
Hope this helps!
The questions asking here is basically asking for half of the hypotenuse
Pythagorean Theorem= a^2 + b^2 = c^2
40^2 + 30^2 = c^2
1600 + 900 = c^2
2500 = c^2
square root of 2500 is 50
C = 50
half of C is 25
BE is 25