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Makovka662 [10]
3 years ago
13

The velocity of a plane that travels 450.0 km due north in 3.500 hours is

Physics
2 answers:
dalvyx [7]3 years ago
6 0

Answer : The velocity of a plane that travels 450.0 km due north in 3.500 hours is, 35.71 m/s

Solution : Given,

Distance = 450 km = 450000 meter     (1 km = 1000 m)

Time = 3.5 hours = 12600 second        (1 hr = 3600 s)

Velocity : It is defined as the displacement divided by the time. It is vector quantity. That means both magnitude and the direction are needed to define the velocity. The S.I unit of velocity is meter per second (m/s).

Formula used :

Velocity=\frac{Displacement}{Time}

Now put all the given values in this formula, we get

Velocity=\frac{450000m}{12600s}=35.71m/s

Therefore, the velocity of a plane that travels 450.0 km due north in 3.500 hours is, 35.71 m/s

ddd [48]3 years ago
4 0
I believe it's <span> 128.6 km/h due north. 
</span>
I hope this helps!
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At a particular temperature, the speed of sound is 330 m/s and its frequency is 990 Hz. Choose the correct wavelength of this so
koban [17]

Answer:

1/3 M

I hope this helps :) sorry its late

8 0
3 years ago
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In the nuclear fission process mass is converted into energy. Determine the total mass that must be converted to energy in one y
brilliants [131]

Answer:

1) Mass that needs to be converted at 100% efficiency is 0.3504 kg

2) Mass that needs to be converted at 30% efficiency is 1.168 kg

Explanation:

By the principle of mass energy equivalence we have

E=mc^{2}

where,

'E' is the energy produced

'm' is the mass consumed

'c' is the velocity of light in free space

Now the energy produced by the reactor in 1 year equals

Energy=Power\times time\\\\\therefore Energy=1\times 10^{9}\times 365\times 24\times 3600\\\\Energy=31.536\times 10^{15}Joules

Thus the mass that is covertred at 100% efficiency is

mass=\frac{Energy}{c^{2}}\\\\mass=\frac{31.536\times 10^{15}}{(3\times 10^{8})^{2}}\\\\mass=\frac{31.536\times 10^{15}}{9\times 10^{16}}\\\\\therefore mass=0.3504kg

Part 2)

At 30% efficiency the mass converted equals

mass|_{30}=\frac{mass|_{100}}{0.3}\\\\mass|_{30}=\frac{0.3504}{0.3}\\\\mass|_{30}=1.168kg

8 0
3 years ago
Whqt do you mean by geo-stationery satellite? Explain.​
Ratling [72]

Answer:

Description: When a geosynchronous satellite is placed directly above the Equator with a circular orbit and angular velocity identical to that of the Earth, the satellite is known as a geostationary satellite

Explanation:

These satellites appear to be stationary above a particular point which is due to the synchronization. This type of satellite provides a distinct benefit of fixing the receiving antennas at one place, hence making them more economical than regular tracking antennas. Over the years, these satellites have helped in revolutionizing the global communications, weather forecasting and television broadcasting. When the orbit of a geosynchronous satellite is not aligned directly over the equator, the orbit is known as an inclined orbit.

8 0
3 years ago
you measured the torque caused by the gyroscope's weight by lifting up the end of the gyroscope (at 7.5 inches). If you measured
DIA [1.3K]

Answer:

i) No, the spring scale does not read a different value

ii) The torque will read a different value, it will reduce

iii) The spring scale does not need to be measured at the center of mass location.

Explanation:

The torque caused by the gyroscope can be given by the relation,

\tau = r × f

\tau = rf cos \theta

The torque measured by the gyroscope varies directly with the distance, r.

A decrease in the distance r will also cause a decrease in the value of the torque measured. When the distance, r is reduced from 7.5 inches to 5 inches, the torque caused by the gyroscope's weight also reduces.

The weight of the gyroscope remains constant despite the reduction in the distance because the weight  of the gyroscope is not a function of the distance from the gyroscope. Therefore, the spring scale will not read a different value.

Yes, the spring scale does not need to be measured from the center of mass location because the weight does not depend on the location of measurement. The reading of the sprig scale remains constant.

3 0
3 years ago
A student was asked to push a large box down the hallway about 35 meters. the task took the student five minutes and a force of
zaharov [31]
Rate of work or Power done by the student can be computed with below formulas.
1. Formula for Work
Work = Force x distance
Force or F = Force applied to the object 
distance or d = displacement

2. Formula for Power
P = Work done / Time it was done or completed

Substituting the values we have,
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Lastly computing for the rate we have,
Power or rate of work = 5250 J / 300 seconds (or 5 min) = 17.5 Joule/S or Watts

Answer is 17.5 watts

5 0
3 years ago
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