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3 years ago

The velocity of a plane that travels 450.0 km due north in 3.500 hours is

Physics

2 answers:

dalvyx [7]3 years ago

6 0

Answer : The velocity of a plane that travels 450.0 km due north in 3.500 hours is, 35.71 m/s

Solution : Given,

Distance = 450 km = 450000 meter (1 km = 1000 m)

Time = 3.5 hours = 12600 second (1 hr = 3600 s)

Velocity : It is defined as the displacement divided by the time. It is vector quantity. That means both magnitude and the direction are needed to define the velocity. The S.I unit of velocity is meter per second (m/s).

Formula used :

$Velocity=\frac{Displacement}{Time}$

Now put all the given values in this formula, we get

$Velocity=\frac{450000m}{12600s}=35.71m/s$

Therefore, the velocity of a plane that travels 450.0 km due north in 3.500 hours is, 35.71 m/s

ddd [48]3 years ago

4 0

I believe it's 128.6 km/h due north.

I hope this helps!

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