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Ivahew [28]
3 years ago
15

Which law of motion describes squeal and oppisit forces of action and reaction​

Physics
1 answer:
Rom4ik [11]3 years ago
4 0

These two forces are called action and reaction forces and are the subject of Newton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects.


Hope this helps! :)

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A transverse wave on a string is described by the wave functiony(x, t) = 0.350 sin (1.25x + 99.6t)where x and y are in meters an
ella [17]

The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.

<h3>How to solve for the time interval</h3>

We have y = 0.175

y(x, t) = 0.350 sin (1.25x + 99.6t) = 0.175

sin (1.25x + 99.6t) = 0.175

sin (1.25x + 99.6t) = 0.5

99.62 = pi/6

t1 = 5.257 x 10⁻³

99.6t = pi/6 + 2pi

= 0.0683

The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.

b. we have k = 1.25, w = 99.6t

v = w/k

99.6/1.25 = 79.68

s = vt

= 79.68 * 0.0683

= 5.02

Read more on waves here

brainly.com/question/25699025

#SPJ4

complete question

A transverse wave on a string is described by the wave function y(x, t) = 0.350 sin (1.25x + 99.6t) where x and y are in meters and t is in seconds. Consider the element of the string at x=0. (a) What is the time interval between the first two instants when this element has a position of y= 0.175 m? (b) What distance does the wave travel during the time interval found in part (a)?

7 0
2 years ago
light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance li
lapo4ka [179]

Answer:

The distance traveled in 1 year is: 3.143*10^{16}ft

Explanation:

Given

s = 982,080,000 ft/s --- speed

t = 32,000,000 s --- time

Required

The distance traveled

This is calculated as:

Speed = \frac{Distance}{Time}

So, we have:

Distance = Speed * Time

This gives:

Distance = 982,080,000 ft/s * 32,000,000 s

Distance = 982,080,000  * 32,000,000ft

Distance = 3.143*10^{16}ft -- approximated

5 0
3 years ago
A cycle track is 500 metres long. Amy completes 10 laps. She travelled at an average speed of 12.5 metres per second. She puts o
yanalaym [24]
The fast lap is irrelevant to the question, because it didn't happen
until after the 9 laps that you're interested in.

To be perfectly technical about it, we don't actually have enough
information to answer the question.  You told us her average speed
for 10 laps, but we don't know anything about how her speed may
have changed during the whole 10 laps.  For all we know, maybe
she took a nap first, and then got up and drove 10 laps at the speed
of 125 metres per second.  That would produce the average speed
of 12.5 metres per second and we would never know it  Why not ?
That's only 280 miles per hour.  Bikes can do that, can't they ?

IF we can assume that Amy maintained a totally steady pace through
the entire 10 laps, then we could say that her average for 9 laps was
also 12.5 metres per second.
5 0
3 years ago
Shane is riding his bike at a speed of 10m/s. He isn't watching carefully where he is going and almost hit a tree. He abruptl
Rom4ik [11]

Answer:

2.5m/s²

Explanation:

a = v/t

Where;

V = velocity (m/s)

a = acceleration (m/s²)

t = time (s).

According to the information provided in this question,

a = ?

v = 10m/s

t = 4

a = 10/4

a = 2.5m/s²

4 0
3 years ago
The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength o
Ilia_Sergeevich [38]
V = 331 m/s
Wavelength = velocity of sound/ frequency
Frequency = velocity of sound / wavelength = 331 m/s : 0.6 m
Frequency = 551.67 s^-1 = 551.67 Hz 
4 0
4 years ago
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