You would also need to know the mol of sodium. After knowing the mol, write down the reaction;
Na + H20 -> NaOH + H2
Use the mol ratio, to find the amount of mol of sodium hydroxide. (Remember to balance the equation first)
After you have the necessary variables, use the following formula:
mass of sodium hydroxide = mol of sodium hydroxide x molar mass (relative/formula mass of sodium hydroxide)
That is how you will find the mass of sodium hydroxide.
        
             
        
        
        
Answer:
   The mechanism of this reaction i shown on the second uploaded image
The final product of the reaction is shown on the third uploaded image
The hydroxide would be first mixed with the ketone group before the aldehyde is added  
Explanation:
The compound given in the question is 2,2-dimethylpropanal (pivalaldehyde) the structural formula is shown on the first uploaded image 
looking at the structurally formula we can see that the hydroxide promoted reaction of this compound would be between the ketone and aldehyde functional group present in this compound in the presence of a hydroxide 
Now this process of the reaction is this 
     The  is first  made to react with the ketone group
 is first  made to react with the ketone group 
      Then the aldehyde is added 
      What happens is that that the  would search for an acidic proton because it is a base and this acidic proton is present in ketone and absent in aldehyde group hence the reason for the first reaction with the ketone group before the aldehyde is added
 would search for an acidic proton because it is a base and this acidic proton is present in ketone and absent in aldehyde group hence the reason for the first reaction with the ketone group before the aldehyde is added  
 
        
             
        
        
        
<u>Answer :</u>
Part 13:
The balanced chemical reaction will be:

Part 14:
The balanced chemical reaction will be:

Part 15:
The balanced chemical reaction will be:

<u>Explanation :</u>
Balanced chemical reaction : It is defined as the reaction in which an individual element of an atom present on reactant side must be equal to product side.
Part 13:
The balanced chemical reaction will be:

Part 14:
The balanced chemical reaction will be:

Part 15:
The balanced chemical reaction will be:

 
        
             
        
        
        
Answer:
b.Rearrange the two equations to make each variable the focus (you will end up with three variations for each equation).
 
        
             
        
        
        
Explanation:
Half life of zero order and second order depends on the initial concentration. But as the given reaction slows down as the reaction proceeds, therefore, it must be second order reaction. This is because rate of reaction does not depend upon the initial concentration of the reactant.
a. As it is a second order reaction, therefore, doubling reactant concentration, will increase the rate of reaction 4 times. Therefore, the statement  a is wrong.
b. Expression for second order reaction is as follows:
![\frac{1}{[A]} =\frac{1}{[A]_0} +kt](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%20%3D%5Cfrac%7B1%7D%7B%5BA%5D_0%7D%20%2Bkt)
the above equation can be written in the form of Y = mx + C
so, the plot between 1/[A] and t is linear. So the statement b is true.
c. 
Expression for half life is as follows:
![t_{1/2}=\frac{1}{k[A]_0}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B1%7D%7Bk%5BA%5D_0%7D)
As half-life is inversely proportional to initial concentration, therefore, increase in concentration will decrease the half life. Therefore statement c is wrong.
d. 
Plot between A and t is exponential, therefore there is no constant slope. Therefore, the statement d is wrong