A possible mechanism for the overall reaction br2 (g) + 2no (g) → 2nobr (g) is no (g) + br2 (g) nobr2 (g) (fast) nobr2 (g) + no
(g) k2→ 2nobr (slow) the rate law for formation of nobr based on this mechanism is rate = ________. a possible mechanism for the overall reaction br2 (g) + 2no (g) 2nobr (g) is no (g) + br2 (g) nobr2 (g) (fast) nobr2 (g) + no (g) 2nobr (slow) the rate law for formation of nobr based on this mechanism is rate = ________. k1[br2]1/2 (k2k1/k-1)[no][br2]2 (k1/k-1)2[no]2 k1[no]1/2 (k2k1/k-1)[no]2[br2]
The overall reaction is: Br₂(g) + 2 NO(g) ↔ 2 NOBr(g) rate law = k [Br₂][NO]²
The first step of the overall reaction is: NO(g) + Br₂(g) K₁⇄⇄K-1 NOBr₂(g) rate law 1 = k₁ [Br₂][NO] or rate law 2 = k-1 [NOBr₂]
The second step of the overall reaction is: NOBr₂(g) + NO(g) →K₂→ 2 NOBr rate law 3 = k₂[NOBr₂][NO]
So, rate law of overall reaction can be obtained as follows: (rate law 1)*(rate law 3) / (rate law 2) = [(k₁[Br₂][NO])* (K₂[NOBr₂][NO])] / k₋₁[NOBr₂] = [k₁k₂/k₋₁][NO]²[Br₂] So the correct answer is: [k₁k₂/k₋₁][NO]² [Br₂]
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