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3 years ago

What is the density of an object with a mass of 7.92g and a volume of 3.25mL?

1 answer:

6 0

Hey there!

Using your density formula, D=M/V where D represents the density, M represents the mass, and V represents the volume, you can plug in your given values to find the density.

Knowing that your mass is 7.92 grams, and your volume is 3.25 mL, you can find the density by setting up this expression:
7.92/3.25

Now, simplify:
7.92/3.25
≈2.44

Therefore, your density of the object would be approximately 2.44 grams per mL.

Hope this helps and have a marvelous day! :)

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Which pair of samples contains the same number of oxygen atoms in each compound?0.20 mol Ba(OH)2 and 0.20 mol H2SO40.20 mol Br2O

Whitepunk [10]

Answer:

0.20 mol Br2O and 0.20 mol HBrO have the same number of oxygen atoms

Explanation:

0.20 mol Ba(OH)2 and 0.20 mol H2SO4

In Ba(OH)2 there are 2 moles of O atoms in every mol of Ba(OH)2.

Number of O atoms in 0.20 moles Ba(OH)2 = 2*0.20 = 0.40 moles O atom

In H2SO4 there are 4 moles of O atoms for every mol of H2SO4.

Number of O atoms in 0.20 moles H2SO4 = 4*0.20 = 0.80 moles O atom

⇒ 0.20 mol Ba(OH)2 and 0.20 mol H2SO4 do not have the same number of oxygen atoms.

0.20 mol Br2O and 0.20 mol HBrO

In Br2O there is 1 mol of O atoms in every mol Br2O

Number of O atoms in 0.20 moles Br2O = 0.20*1 = 0.20 moles O atom

In HBrO there is 1 mol of O atom in every mol HBrO

Number of O atoms in 0.20 moles HBrO = 0.20 *1 = 0.20 moles O atom

⇒ in 0.20 moles Br2O and 0.20 moles HBrO we have the same number of oxygen atoms

0.20 moles of Oygen contains: = 0.20 * 6.022*10^23 = 1.2 *10^23 O atoms

0.10 mol Fe2O3 and 0.50 mol BaO

In Fe2O3 there are 3 moles of O atoms in every mol of Fe2O3

Number of O atoms in 0.10 moles Fe2O3 = 0.10 * 3 = 0.30 moles O atom

In BaO there is 1 mol of O atoms in every mol BaO

Number of O atoms in 0.50 mol BaO = 1*0.50 = 0.50 moles O atom

⇒ 0.10 mol Fe2O3 and 0.50 mol BaO do not have the same number of oxygen atoms.

0.10 mol Na2O and 0.10 mol Na2SO4

In Na2O there is 1 mol of O atoms in every mol of Na2O

Number of O atoms in 0.10 mol Na2O = 1*0.10 = 0.10 moles O atom

In Na2sO4 there are 4 moles of O atoms in every mol of Na2SO4

Number of O atoms in 0.10 mol Na2SO4 = 4*0.10 = 0.40 moles O atom

⇒ 0.10 mol Na2O and 0.10 mol Na2SO4 do not have the same number of oxygen atoms.

4 0

3 years ago

How does sand becomes a form

Sonbull [250]

I think sand is just glass and other stuff

6 0

2 years ago

Read 2 more answers

Suppose you burn a substance in the air (reactants) and produce smoke and ash (products). The law of conservation of mass states

Aleks04 [339]

Answer:

The same as can best fill the space

Explanation:

The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction. For example, when wood burns, the mass of the soot, ashes, and gases, equals the original mass of the charcoal and the oxygen when it first reacted.

It shows that when wood burns, it combines with oxygen and changes not only to ashes, but also to carbon dioxide and water vapor. The gases float off into the air, leaving behind just the ashes. Suppose you had measured the mass of the wood before it burned and the mass of the ashes after it burned. Also suppose you had been able to measure the oxygen used by the fire and the gases produced by the fire. What would you find? The total mass of matter after the fire would be the same as the total mass of matter before the burning.

3 0

3 years ago

Read 2 more answers

I am new to Chemistry. How would I figure the density of mercury if 205ml has a mass of 2790g

Sati [7]

Density=mass/volume. Put the mass (2790g) over the volume (205mL)

Density= 2790g/205mL
Your answer should be in g/mL.
Hope this helped! :)

3 0

3 years ago

what volume (in ml) of 1.508 m h3po4 (aq) would be required to react completely with 11.73 ml of 1.006 m ca(oh)2? (aq)

alexdok [17]

The amount of 4.86 ml needed to completely react with 11.73 ml of 1.006 m ca(oh)2 is 4.86 ml.

given data to be calculated:-

Ca3(PO4)2 (s) + 6H2O can be used to calculate this: 3Ca(OH)2 (aq) + 2H3PO4 (aq) (l)

ca moles (OH)

2 present 11.00 moles of H3PO4 are required; 7.33 moles of H3PO4 in a volume of ml are required; 7.33/1.508 = 4.86.

<h3>How do moles react to an increase in volume?</h3>

The direction that creates more moles of gas benefits from an increase in volume, and since there are more moles of products in this case, the reaction will shift to the right and produce more moles of products.

To know more about mole visit:-

brainly.com/question/26416088

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6 0

1 year ago