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3 years ago

Which system of equations has a solution of approximately (1.8,-0.9)

Mathematics

2 answers:

Solnce55 [7]3 years ago

3 0

Solve the equation systems or set the values x = 1.8 and y = -0.9 on the equation and check the equality.

6x - 5y = 15

L = 6(1.8) - 5(-0.9) = 10.8 + 4.5 = 15.3

R = 15

L ≈ R

x + 2y = 0

L = 1.8 + 2(-0.9) = 1.8 - 1.8 = 0

L = R

4x + 5y = 8

L = 4(1.8) + 5(-0.9) = 7.2 - 4.5 = 2.7

R = 8

L ≠ R

x - 2y = 4

L = 1.8 - 2(-0.9) = 1.8 + 1.8 = 3.6

R = 4

L ≈ R

4x + 5y = 8

L = 4(1.8) + 5(-0.9) = 7.2 - 4.5 = 2.7

R = 8

L ≠ R

6x - 5y = 15

L = 6(1.8) - 5(-0.9) = 10.8 + 4.5 = 15.3

R = 15

L ≈ R

x - 2y = 4

L = 1.8 - 2(-0.9) = 1.8 + 1.8 = 3.6

R = 4

L ≈ R

We have two probability solutions: A and D.

But I think, Your answer is A.

Andrews [41]3 years ago

3 0

6x - 5y = 15

L = 6(1.8) - 5(-0.9) = 10.8 + 4.5 = 15.3

R = 15

L ≈ R

x + 2y = 0

L = 1.8 + 2(-0.9) = 1.8 - 1.8 = 0

L = R

4x + 5y = 8

L = 4(1.8) + 5(-0.9) = 7.2 - 4.5 = 2.7

R = 8

L ≠ R

x - 2y = 4

L = 1.8 - 2(-0.9) = 1.8 + 1.8 = 3.6

R = 4

L ≈ R

4x + 5y = 8

L = 4(1.8) + 5(-0.9) = 7.2 - 4.5 = 2.7

R = 8

L ≠ R

6x - 5y = 15

L = 6(1.8) - 5(-0.9) = 10.8 + 4.5 = 15.3

R = 15

L ≈ R

x - 2y = 4

L = 1.8 - 2(-0.9) = 1.8 + 1.8 = 3.6

R = 4

L ≈ R

Yeah so your answer is gonna be

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3 years ago

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aleksley [76]

Answer:

a) A student travelling to school on public transport: 15/52 or 0.231

b) A student walking to school: 16/52 or 0.308

c) A student not cycling to school: 43/52 or 0.827

Step-by-step explanation:

Total people = 52

Travel Method Frequency

Public Transport 12

Car 15

Cycle 9

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Find the relative frequency of.

The formula used will be: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

a) A student travelling to school on public transport:

Given Frequency: 12

Size of sample space: 52

Apply formula: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

Fraction = 12/52

Decimal = 0.231

b) A student walking to school

Given Frequency: 16

Size of sample space. 52

Apply formula: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

Fraction = 16/52

Decimal = 0.308

c) A student not cycling to school.

We will consider all students except those who cycle.

12+15+16 = 43

Given Frequency: 43

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Apply formula: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

Fraction = 43/52

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3 years ago

Milene é doceira e a seguir está uma representação dos bombons que ela fez no dia. Do total dos bombons que fez 2/3 são de coco.

Paha777 [63]

Answer:

16 bombons de coco

Step-by-step explanation:

A partir da pergunta, somos instruídos a fingir que o número total de bombons (chocolate) que ela fez = 24 bombons

Do total de chocolates que ele fez, 2/3 são de coco.

Portanto, a quantidade que representa os doces de coco é representada como:

2/3 × 24

= 16

Portanto, a quantidade de bombons de coco = 16

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4 years ago

Naoya read a book cover to cover in a single session, at a rate of 555555 pages per hour. After reading for 444 hours, he had 33

siniylev [52]

Answer:

<h3>The function formula for the number of pages left to read is given by P(t)=55(10-t).</h3>

Step-by-step explanation:

Given that "Naoya read a book at a rate of 55 pages per hour".

After reading book for 4 hours, he had 330 pages remaining to read.

In 4 hours, Naoya must read is given by

$\frac{55}{1hr}\times 4hr$ ( by given)

$=220$

<h3>∴ In 4 hours, Naoya must read 220 pages</h3>

From the given there were 330 pages remaining to read at the time,

The total number of pages is given by

=220+330

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<h3>∴ The total number of pages is 550 </h3>

For each hour of reading, Naoya reads 55 pages, so the number of pages he finished reading by the "t"th hour is given by 55t

Let P(t) be the number of pages to read where P is a function of time t (measured in hours)

So the number of pages left to read is given by

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3 years ago

Bruce's hourly wage increased from $12.00 to $13.00. What is the percent of increase?

vladimir1956 [14]

Answer:

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Step-by-step explanation:

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3 years ago