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4 years ago

Help algebra. one question.

Mathematics

1 answer:

oee [108]4 years ago

6 0

Jenny's total earnings:

total earnings = (hours worked on design)*40 + (hours worked on maintenance)*35

average earnings = total earnings / hours worked

So far she has

total earnings = 18*40 + 20*35 = $1420

which is an average per hour = $1420/38hr = $37.37

How many more hours on webdesign: x

so that

($1420+x*$40)/(38+x)=38

Now solve for x - this I let you do. My results is x=12 (you can verify by plugging it iback into the equation).

The answer is Jenny needs to work 12 more hours to claim an average earnings of $38/hr. Lmk if you have questions.

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2 years ago

Evelyn wants to estimate the percentage of people who own a tablet computer she surveys 150 indvidals and finds that 120 own a t

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Answer:

The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%

Step-by-step explanation:

Confidence interval for the proportion of people who own a tablet:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

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For this problem, we have that:

$n = 150, \pi = \frac{120}{150} = 0.8$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.576$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{150}} = 0.7159$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{150}} = 0.8841$

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Multiply the proportion by 100.

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0.8841*100 = 88.41%

The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers