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3 years ago

What happens when a chemical change takes place?

2 answers:

5 0

<span>When chemical change takes place, the atoms in the reactants rearrange and bond together differently to form one or more new products with different characteristics. </span>

Natali [406]3 years ago

3 0

Form one or more new products with different characterstics

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A ____ is one of the tiny dots of light that form a grid on your screen.

Degger [83]

Hi there

The answer is pixel

Hope this helps

8 0

2 years ago

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Noble gases, such as argon and neon, are known for being extremely non-reactive. Neon and argon are non-reactive because they A.

Greeley [361]

B. have eight electrons in their outer shell

3 0

3 years ago

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An object with mass M is attached to the end of a string and is raised vertically at a constant acceleration of g 10 . If it has

RoseWind [281]

Answer:

Work done against gravity will be

W = Mgℓ

Explanation:

Work done to raise the mass from ground to given height is against gravity

So here work done is given by the formula

$W = F.d$

here we know that

$F = Mg$

it is the force due to gravity which is also known as weight

so here distance moved by the object is given as

d = ℓ

now work done is given as

W = Mg ℓ

8 0

3 years ago

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An old-fashioned LP record rotates at 33 1/3 RPM

Ksenya-84 [330]

Answer:

Part a) $\frac{5}{9}\ \frac{rev}{sec}$

Part b) $\frac{9}{5}\ \frac{sec}{rev}$

Explanation:

Part a) what is its frequency, in rev/s

we have that

An old-fashioned LP record rotates at 33 1/3 RPM

$33\frac{1}{3}\ \frac{rev}{min}$

Convert mixed number to an improper fraction

$33\frac{1}{3}\ \frac{rev}{min}=\frac{33*3+1}{3}=\frac{100}{3}\ \frac{rev}{min}$

Remember that

$1\ min=60\ sec$

Convert rev/min to rev/sec

$\frac{100}{3}\ \frac{rev}{min}=\frac{100}{3}(\frac{1}{60})=\frac{100}{180}\ \frac{rev}{sec}$

Simplify

$\frac{5}{9}\ \frac{rev}{sec}$

Part b) what is it period, in seconds

we know that

The period is the reciprocal of the frequency

therefore

the frequency is

$\frac{9}{5}\ \frac{sec}{rev}$

4 0

2 years ago

An object of mass m moving at a speed of v1 possesses kinetic energy that is equal to KE1. When the object's speed is doubled, t

Vera_Pavlovna [14]

Answer:

KE₂ = 4KE₁

Explanation:

KE₁ = ½mv₁²

KE₂ = ½mv₂²

KE₂ = ½m(2v₁)²

KE₂ = 4(½mv₁²)

KE₂ = 4KE₁

7 0

2 years ago