The force between charged particles is calculated through the Coulomb's law,
F = kQ₁Q₂/d²
From the equation, it can be deduced that the force is linearly directly proportional to the charge. This means that when the charge is doubled, the force is likewise doubled. Therefore, the compared to force on b, the force on a is twice.
Answer:
-16°C
Explanation:
PV = nRT
V and n are constant.
P / T = P / T
(2 atm + 1 atm) / (266 K) = (1.9 atm + 1 atm) / T
T = 257.1 K
T = -16°C
Answer:
4.39 x 10^-19 J
Explanation:
q1 = 1.6 x 10^-19 C
q2 = - 1.6 x 10^-19 C
r1 = 3 x 10^-10 m
r2 = 7 x 10^-10 m
The formula for the potential energy is given by
U1 = k q1 q2 / r1 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (3 x 10^-10)
U1 = - 7.68 x 10^-19 J
U2 = k q1 q2 / r2 = - (9 x 10^9 x 1.6 x 10^-19 x 1.6 x 10^-19) / (7 x 10^-10)
U2 = - 3.29 x 10^-19 J
Change in potential energy is
U2 - U1 = - 3.29 x 10^-19 + 7.68 x 10^-19 = 4.39 x 10^-19 J
Answer:
I'm pretty sure it shows a direct relationship
Explanation: