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aliya0001 [1]
3 years ago
12

Ancient species found in just one region, whose close relatives have all gone extinct, are designated __________.

Physics
1 answer:
Molodets [167]3 years ago
3 0

Ancient species living in earth with all its close relatives dead are called living fossils.

<h3><u>Explanation:</u></h3>

Living fossils are interesting as well important creations of nature. Let's take an example of a plant <em>Ginkgo biloba</em>. Its a plant of gymnosperm family along with pine and fir, but belongs to the order Ginkgoales. In this order, Gingko biloba is the only plant that's alive till now, all the other species are dead.

Living fossils give us important informations about the adaptation that used to prevail in earth that lead to survival of species in contemporary times. It also establishes relationships between the two or more phyla of organisms in a taxonomic way.

Animal living fossils are lungfish, horse shoe crab, coelacanth fish, Tuatara, lobe finned fishes etc.

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Explain a situation in which you can accelerate even though your speed doesn't change
ANTONII [103]
You can accelerate by changing direction, even though you don't speed up/down. Remember that acceleration is a vector so, it has a direction and a magnitude. That's why this works! Hope it helps.
4 0
4 years ago
Read 2 more answers
The drill used by most dentists today is powered by a small air-turbine that can operate at angular speeds of 350000 {\rm rpm} .
damaskus [11]

Answer:

5833.33

Explanation:

\alpha = Angular acceleration

\theta = Number of revolutions

\omega_i = Initial angular speed = 0

t = Time taken = 2 s

Final angular speed

\omega_f=\dfrac{350000}{60}=5833.33\ rps

From the equation of rotational motion we have

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{5833.33-0}{2}\\\Rightarrow \alpha=2916.665\ rev/s^2

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \theta=0\times t+\dfrac{1}{2}\times 2916.665\times 2^2\\\Rightarrow \theta=5833.33\ rev

The number of revolutions is 5833.33

6 0
3 years ago
Important nuclei of the indirect (multineuronal) system that receive impulses from the equilibrium apparatus of the inner ear an
Lera25 [3.4K]

Answer:

B. Vestibular nuclei

Explanation:

The nerve information generated by the vestibular receptors travels through the vestibular portion of the eighth pair that penetrates the brain stem at the level of the brain stem bridge. At this level there are four vestibular nuclei, which receive the synapses of these axons, coming from the ridges and macules. The semicircular ducts predominantly terminate in the superior and medial nuclei. While the fibers coming from the macules end on the lateral, medial and inferior nuclei. Some fibers of the eighth pair end in the flocculonodular lobe of the cerebellum, <u>these connections play an important role in controlling posture and balance.</u>

From the vestibular nuclei, two bundles of fibers descending to the spinal cord originate from the medial and lateral vestibular spinal bundles and a bundle of fiber that rises in the brain stem that participates in the coordination of eye movements, the medial longitudinal fascicle, which participates in Rotational nystagmus This system also participates in an important way in the control of some ocular movements by the fibers that it contributes to the medial longitudinal fascicle, which is a structure that interconnects the motor nuclei of the extrinsic muscles of the eyeballs VI or abdicens nucleus (abductor) on one side and IV or pathetic nucleus (trochlear) and III or nucleus of the common ocular motor (oculomotor) on the opposite side.

6 0
3 years ago
A 25 N force at 60° is required to set a crate into motion on a floor. What is the value of the static friction?
True [87]
The normal force of the force given is calculated through the equation,
 
                                 Fn = F(sin θ)
where Fn is the normal force, F is the force, and θ is the angle. 
  
                                Fn = (25 N)(sin 60°) = 21.65 N

The x-component of the force applied is,
                               Fx = (25 N)(cos 60°) = 12.5 N

The value of the coefficient of static friction is calculated through the equation,
                              F = μFn
                              μ = Fx / Fn = 12.5 N / 21.65 N = 0.577
3 0
3 years ago
A 45.5-turn circular coil of radius 4.85 cm can be oriented in any direction in a uniform magnetic field having a magnitude of 0
il63 [147K]

Answer:

4.399 Nm

Explanation:

The maximum Torque on a coil is given as,

τ = BNIA...................... Equation 1

Where τ = Maximum torque exerted on the coil, B = Magnetic Field, N = Number of turns, I = Current, A = Area.

Given: N = 45.5 Turns, B = 0.49 T, I = 26.7 mA = 0.0267 A,

A = πr², Where r = radius of the coil, r= 4.85 cm = 0.0485 m

A = 3.14(0.0485)²

A = 7.39×10⁻³ m².

Substitute into equation 1

τ  = 45.5×0.49×26.7×7.39×10⁻³

τ = 4.399 Nm

3 0
3 years ago
Read 2 more answers
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