Answer:
The answer to the question is
The object would fall 57.625 m in the first 5 seconds
Explanation:
To solve the question, we note that
the height of fall = 490 ft = 149.352 m
Time to touch the ground = 7 seconds
We are required to find out how far the object falls in the first 5 seconds
We apply the relation
S = u·t + 0.5×g·t ² = We then have
149.352 = U×7+0.5*9.81*49 From where u = -13 m/s
Therefore to find how far it falls in the first 5 seconds, we have
-13*5 + 0.5*9.81*25 = 57.625 m
Answer:
De cual Tema??? jajaja no se que necesitas
Answer:
4th answer
Explanation:
The gradient of a distance-time graph gives the speed.
gradient = distance / time = speed
Here, the gradient is a constant till 30s. So it has travelled at a constant speed. It means it had not accelarated till 30s. and has stopped moving at 30s.
<h2>
It takes 6.78 seconds to complete 12 dribbles.</h2>
Explanation:
Frequency of dribble = 1.77 Hz
That is
Number of dribbles in 1 second = 1.77
Now we need to find how long does it take for you to complete 12 dribbles.
Time taken for 12 dribbles = 12 x Time taken for 1 dribble
Time taken for 12 dribbles = 12 x 0.565
Time taken for 12 dribbles = 6.78 seconds
It takes 6.78 seconds to complete 12 dribbles.
Answer:
Final momentum after a head on collision is -2kgm/s
Explanation:
One ball moves to the right and the other moves opposite and momentum is a vector quantity so that considering the direction
Initial momenta are P₁=2x3=6kgm/s P₂=4x(-2)=-8kgm/s
Final momentum is the vector sum of P(final)= 6-8= -2 kgm/s
