Answer:
QC = 122 KJ
QH = 2.64 x 122 = 322 KJ
Explanation:
TH = 500 Degree C = 500 + 273 = 773 K
TC = 20 degree C = 20 + 273 = 293 K
W cycle = 200 KJ
Use the formula for the work done in a cycle
Wcycle = QH - QC
200 = QH - QC ..... (1)
Usse
TH / TC = QH / QC
773 / 293 = QH / QC
QH / QC = 2.64
QH = 2.64 QC Put it in equation (1)
200 = 2.64 QC - QC
QC = 122 KJ
So, QH = 2.64 x 122 = 322 KJ
Momentum can be defined by the formula p=m*V (where m is mass and V is velocity) so if we plug in these numbers:
p = 2kg * 6m/s
p = 12 kgm/s
Answer:
1. 218.55 N
2. 
3. 
Explanation:
Part 1;
Net force
where m is mass, g is gravitational force and
is the angle of inclination

Frictional force,
is given by
where
is the coefficient of static friction


Since
, therefore, the block doesn’t slip and the frictional force acting is mgh=218.55N
Part 2.
Using the relationship that
Frictional force 



The maximum angle of inclination 

Part 3:
Net force on the object is given by
where
is the coefficient of kinetic friction

= 9.8 ( sin 38 - (0.51) cos 38 )
= 
Answer:
B
Explanation:
Nuclear fission is the process of splitting apart nuclei. When nuclei fission energy is released. So much energy is released that there is a measurable decrease in mass, from the mass-energy equivalence. This means that some of the mass is converted to energy.