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zloy xaker [14]
3 years ago
5

The diagram below shows some subatomic particles. A diagram similar to a flowchart starts with a circle labeled Atom. From there

, a line leads to a small circle labeled Electron and a larger one labeled Nucleus. From nucleus, two lines lead to a group of circles, labeled Neutrons and protons. From there, two lines lead to a circle surrounding two blue and one orange smaller circles. One of the blue circles is labeled with a question mark. What is the particle that is labeled with a question mark (?) in the diagram?
Chemistry
2 answers:
barxatty [35]3 years ago
7 0

Answer:

B) Quark

Explanation:

Aleksandr-060686 [28]3 years ago
6 0

Answer:

The shaded area 2 is likely to have subatomic particle that are constantly in motion. I took the test and I got it right

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1. An atom of an elephant has atomic mass of 39 and has number of neutrons as 20 calculate protons number.
r-ruslan [8.4K]

Answer:

See Explanation

Explanation:

1) Let us recall that;

Mass number = number of protons + number of neutrons

Where;

Number of protons = ?

Number of neutrons =20

Mass number =39

Number of protons = mass number - number of neutrons

Mass of protons =39 - 20= 19 protons

2) Atomic number = 13

Number of neutrons =14

Then the mass number =13 +14 =27

The symbol of the element is 27X13

The number of protons= the number of electrons =13

The atomic number is the same as the proton number =13

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A 0.750 g sample of tin is oxidized with nitric acid to form tin oxide. Calculate the
irakobra [83]

A 0.750 g sample of tin is oxidized with nitric acid to form tin oxide.  if the original tin sample gained 0.21 g of oxygen, the empirical formula of tin oxide is SnO₂.

A 0.750 g sample of tin is oxidized with nitric acid to form tin oxide.  if the original tin sample gained 0.21 g of oxygen, the mass of tin oxide is:

mSn_xO_y = mSn + mO = 0.750 g + 0.21 g = 0.96 g

Then, we will calculate the mass percent of each element in the oxide.

\% Sn = \frac{0.750g}{0.96g} \times 100\% = 78\%\\\\\% O = \frac{0.21g}{0.96g} \times 100\% = 22\%

Next, we will divide each percentage by the atomic mass of the element.

Sn: 78/118.71 = 0.66\\\\O: 22/16.00 = 1.4

Finally, we will divide both numbers by the smallest one, i.e. 0.66.

Sn: 0.66/0.66 = 1\\\\O: 1.4/0.66 \approx 2

The empirical formula of tin oxide is SnO₂.

A 0.750 g sample of tin is oxidized with nitric acid to form tin oxide.  if the original tin sample gained 0.21 g of oxygen, the empirical formula of tin oxide is SnO₂.

Learn more: brainly.com/question/1363167

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