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jarptica [38.1K]
3 years ago
12

Write two different word phrases for the expression (52+8) 30

Mathematics
2 answers:
VMariaS [17]3 years ago
8 0

Answer:

(52+8)30 → 'Thirty times the sum of numbers fifty two and eight'.

52\times 30+8\times 30 → 'Fifty-two times thirty with sum of eight times thirty'.

Step-by-step explanation:                  

Given : Expression (52+8)30

To find : Write two different word phrases for the expression ?

Solution :

Writing the number in word phrase is expressing each operation and number in word form.

Taking expression as (52+8)30

There is a sum of 52 and 8 number and 30 is multiplied to them.

So, (52+8)30 → 'Thirty times the sum of numbers fifty two and eight'.

Taking expression as 52\times 30+8\times 30

There is a product of 52 and 30 addition with product of 8 and 30.

So, 52\times 30+8\times 30 → 'Fifty-two times thirty with sum of eight times thirty'.

zepelin [54]3 years ago
3 0

Answer:

1. The product of thirty and eight more than fifty-two.

2. Thirty times the sum of eight and fifty-two

Step-by-step explanation:

 1) 52+8 (eight more the fifty-two )

      52+8 (The product of thirty and eight more than fifty-two.)

       

2) 52+8 (The sum of eight and fifty-two)

     52+8 (Thirty times the sum of eight and fifty-two)

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coldgirl [10]

Answer:

none

Step-by-step explanation:

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6 0
4 years ago
he weight of male babies less than months old in the United States is normally distributed with mean pounds and standard deviati
Degger [83]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: Weight of a male baby (pounds)

X~N(μ;σ²)

μ= 11.5 pounds

σ= 2.7 pounds

a) Find the 81st percentile of the baby weights.

This percentile is the value that separates the bottom 81% of the distribution from the top 19%

P(X≤x₁)= 0.81

For this you have to use the standard normal distribution. First you have to look the 81st percentile under the Z distribution and then "translate" it to a value of the variable X using the formula Z= (X- μ)/σ

P(Z≤z₁)= 0.81

z₁= 0.878

z₁= (x₁- μ)/σ

z₁*σ= x₁- μ

(z₁*σ) + μ= x₁

x₁= (z₁*σ) + μ

x₁= (2.7*0.878)+11.5

x₁= 13.8706 pounds

b) Find the 10th percentile of the baby weights.

P(X≤x₂)= 0.10

P(Z≤z₂)= 0.10

z₂= -1.282

z₂= (x₂- μ)/σ

z₂*σ= x₂- μ

(z₂*σ) + μ= x₂

x₂= (z₂*σ) + μ

x₂= (2.7*-1.282)+11.5

x₂= 8.0386 pounds

c) Find the first quartile of the baby weights.

P(X≤x₃)= 0.25

P(Z≤z₃)= 0.25

z₃= -0.674

z₃= (x₃- μ)/σ

z₃*σ= x₃- μ

(z₃*σ) + μ= x₃

x₃= (z₃*σ) + μ

x₃= (2.7*-0.674)+11.5

x₃= 9.6802 pounds

I hope this helps!

8 0
3 years ago
Select all that are equivalent to a^2/a^9 <br> Assume a \= 0<br> 1<br> 1<br> DONE
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6 0
3 years ago
1) Give an example of a rational number AND an irrational number. Explain how someone could tell the difference between your two
harina [27]

Answer:

1. Ratoinal= 2

irrrational= 8.34284

A rational number can be put into a fraction while an irrational cannot.

My irrational number is a never-ending decimal that never repeats and my rational number is a whole number.

2.I don't know what it means to terminate. If I convert my rational number into a decimal no it does not repeat any digits because the decimal form of 2 would just be 2.0

3. A repeating decimal can be written and a rational number because it can be put into a fraction. ex; 4/9 is a fraction and in decimal, form it is 0.444444444...

Step-by-step explanation:

3 0
3 years ago
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