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RideAnS [48]
3 years ago
12

What distance will be traveled if you are going 120km/hr for 0.75 hr?

Physics
1 answer:
SVEN [57.7K]3 years ago
5 0

Answer:

60 km

Explanation:

For an object (or a person, such as in this case) moving at constant speed, the speed is equal to the ratio between the distance travelled and the time taken:

where

v is the speed

d is the distance

t is the time taken

In this case, we have:

v = 120 km/h is the speed

t = 30 min = 0.5 h is the time taken

Therefore, we can rearrange the equation to find the total distance travelled:

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Is a 10 year old supposed to be doing algebra
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If he feels like, is interested in it, and is able to grasp it, then why not ? Why not indeed ?
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A car breaks down 3.5 meters away from the side of the road. 2.060 Newtons of
kogti [31]

Answer:

<h2>7.21 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 2.060 × 3.5

We have the final answer as

<h3>7.21 J</h3>

Hope this helps you

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2 years ago
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A sample of 2.50 kg of water is held at a temperature of 100°C. How much energy must be added to completely turn the liquid wate
kap26 [50]

Answer:

Explanation:

Since 100C is the boiling temperature for water, for this problem we don't need to calculate the energy needed to get to the boiling point, just the heat or energy needed to vaporize the water to steam at 100C.

The formula for this is  q=m(delta)

q is Joules of heat needed to vaporize the water to steam at 100C

m is mass in grams

Delta is in Joules per gram and can be looked up for water at this temperature. Here, it is approximately 2260J/g. This online lecture should help ease understanding: https://cabrillo.instructure.com/courses/10267/modules/items/256219

Therefore...

q=2.5g (2260J/g)= 5650J = 5.65kJ

I do not do Physics tutoring but am happy to answer questions here.

7 0
2 years ago
A 1. 30 kg block slides with a speed of 0. 855 m/s on a frictionless horizontal surface until it encounters a spring with a forc
boyakko [2]

a) For 0 compressions:

potential energy = U =  0 J

kinetic energy = k = 0.383 J

total mechanical energy = E = 0.383 J

b) For compression of 1 cm:

potential energy = U = 0.0228 J

kinetic energy = k = 0.155 J

total mechanical energy = E = 0.383 J

c) For compression of 2 cm :

potential energy = U = 0.1104 J

kinetic energy = k = 0.272 J

total mechanical energy = E = 0.383 J

d) For compression of 3cm:

potential energy  = U = 0.248 J

kinetic energy = k = 0.177 J

total mechanical energy = E = 0.383 J

<h3>Method for solving:</h3>

The equations for kinetic energy is:

k= 1/2*m*v^{2}

The equation for elastic potential energy is:

U= 1/2*ks*x^{2}

Where,

m= mass of the block

v= velocity

ks= spring constant

x= displacement of the spring

(a)when compression= 0 cm

U= 1/2*ks*v{2}

U= 1/2*552*(0)^{2}

 = 0 J

Kinetic energy:

k= 1/2*m*x^{2}

k= 1/2*(1.05)*(0.855)^{2}

k= 0.383 J

Mechanical energy:

E= k + U

E= 0.383+0

E= 0.383 J

There will be no work done by friction or any other dissipative force, hence this energy will be conserved, or it will remain constant (like air resistance). This indicates that only spring potential energy will be created from the kinetic energy (there is no thermal energy due to friction, for example).

(b) spring potential = ?

U= 1/2* 457 N/m*(0.01)^{2}

U= 0.0228 J

Since the mechanical energy must remain constant, we may calculate the kinetic energy using the mechanical energy equation:

E= k + U

0.383= k + 0.0228

k= 0.383 - 0.228

k= 0.155

(c)spring constant when x= 0.02

U= 1/2*552*(0.02)^{2}

U= 0.1104 J

Using the equation of mechanical energy:

E= k +U

0.383= k+ 0.1104

k= 0.383 - 0.1104

k= 0.272 J

(d) U= 1/2*552*(0.03)^{2}

U= 0.2484 J

E= 0.383 J

k = E - U

k= 0.383- 0.206

k= 0.177

To learn more about spring potential energy visit:

brainly.com/question/28168175

#SPJ4

3 0
2 years ago
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