Answer:
(a) The value of the ratio m₁/m₂ is 0.581
(b) the acceleration of the combined masses is 1.139 m/s²
Explanation:
Given;
The acceleration of force applied to M₁, a₁ = 3.10 m/s²
The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²
Let this force = F
According Newton's second law of motion;
F = ma
(a) the value of the ratio m₁/m₂
since the applied force is same in both cases, M₁a₁ = M₂a₂
(b) the acceleration of m₁ and m₂ combined as one object under the action force F
F = ma
Therefore, the acceleration of the combined masses is 1.139 m/s²
Answer:
The wavelength of the EM wave is 7.5 * 10⁻⁴ m
Explanation:
The velocity of a wave is related to its wavelength by the following formula;
velocity = wavelength * frequency
For an electromagnetic (EM) wave, its velocity is equal to the velocity of light, c = 3.0 * 10⁸ m/s
Given that the frequency and veloity of the given EM wave in the question is known, its wavelength is calculated as follows:
wavelength = velocity/frequency
where velocity of the EM wave = 3.0 * 10⁸ m/s;
frequency = 4THz = 4 * 10¹² Hz
wavelength = 3.0 * 10⁸m/s / 4 * 10¹² Hz
wavelength = 7.5 * 10⁻⁴ m
Therefore, the wavelength of the EM wave is 7.5 * 10⁻⁴ m
Answer:
The specific heat addition is 773.1 kJ/kg
Explanation:
from table A.5 we get the properties of air:
k=specific heat ratio=1.4
cp=specific heat at constant pressure=1.004 kJ/kg*K
We calculate the pressure range of the Brayton cycle, as follows
n=1-(1/(P2/P1)^(k-1)/k))
where n=thermal efficiency=0.5. Clearing P2/P1 and replacing values:
P2/P1=(1/0.5)^(1.4/0.4)=11.31
the temperature of the air at state 2 is equal to:
P2/P1=(T2/T1)^(k/k-1)
where T1 is the temperature of the air enters the compressor. Clearing T2
11.31=(T2/290)^(1.4/(1.4-1))
T2=580K
The temperature of the air at state 3 is equal to:
P2/P1=(T3/T4)^(k/(k-1))
11.31=(T3/675)^(1.4/(1.4-1))
T3=1350K
The specific heat addition is equal to:
q=Cp*(T3-T2)=1.004*(1350-580)=773.1 kJ/kg
It is the only one that has both a partially molten metallic core and reasonably rapid rotation.
So, the speed of the ball after 2 seconds after free fall is <u>20 m/s</u>.
<h3>Introduction</h3>
Hi ! I'm Deva from Brainly Indonesia. In this material, we can call this event "Free Fall Motion". There are two conditions for free fall motion, namely falling (from top to bottom) and free (without initial velocity). Because the question only asks for the final velocity of the ball, in fact, we may use the formula for the relationship between acceleration and change in velocity and time. In general, this relationship can be expressed in the following equation :
With the following conditions :
- a = acceleration (m/s²)
= speed after some time (m/s)
= initial speed (m/s)- t = interval of time (s)
<h3>Problem Solving</h3>
We know that :
- a = acceleration = 9,8 m/s² >> because the acceleration of a falling object is following the acceleration of gravity (g).
- = initial speed = 0 m/s >> the keyword is free fall
- t = interval of time = 2 s
What was asked :
- = speed after some time = ... m/s
Step by step :
So, the speed of the ball after 2 seconds after free fall is 20 m/s.
