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3 years ago

How many does the stor6 need

Physics

1 answer:

melomori [17]3 years ago

3 0

I there supposed to be a picture here or

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Temperature Dependence of the pH of pure Water

Mamont248 [21]

Answer:

At 100°C, the pH of pure water is 6.14. That is the neutral point on the pH scale at this higher temperature. A solution with a pH of 7 at this temperature is slightly alkaline because its pH is a bit higher than the neutral value of 6.14.

Explanation:

nonde

8 0

3 years ago

Charge is distributed uniformly on the surface of a large flat plate. the electric field 2 cm from the plate is 30 n/c. the elec

AysviL [449]

The electric field produced by a large flat plate with uniform charge density on its surface can be found by using Gauss law, and it is equal to
$E= \frac{\sigma}{2\epsilon_0}$
where
$\sigma$ is the charge density
$\epsilon_0$ is the vacuum permittivity

We see that the intensity of the electric field does not depend on the distance from the plate. Therefore, the strenght of the electric field at 4 cm from the plate is equal to the strength of the electric field at 2 cm from the plate:
$E=30 N/C$

7 0

3 years ago

What would you get if you split a bar magnet in the middle?

ipn [44]

Answer:

I believe it's the first option

5 0

3 years ago

A "sun yacht" is a spacecraft with a large sail that is pushed by sunlight. Although such a push is tiny in everyday circumstanc

guajiro [1.7K]

Answer:

acceleration = 0.022 m/s^2

distance = 8.3 x 10^7 m

speed = 1.9 x 10 ^3 m/s

Explanation:

the parameters given are:

mass = 900kg

force = 20N

from the formula force = mass x acceleration

acceleration = force / mass

acceleration = 20 / 900

acceleration = 0.022 m/s^2

distance travelled in 1 day (86,400 seconds) = (1/2) x a x t^2

(1/2) x 0.022 x (86,400^2) = 8.3 x 10^7 m

speed of the sun yatch (v) = a x t

0.22 x 86400 = 1.9 x 10 ^3 m/s

8 0

3 years ago

A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. What is

loris [4]

Answer:

The acceleration of the crate is $1.82\ m/s^2$ .

Explanation:

Given that,

Force, F = 750 N

Mass of the crate, m = 250 kg

The coefficient of friction is 0.12.

We need to find the acceleration of the crate. The net force acting on the crate is given by :

$F=ma\\\\F-f=ma$

f is frictional force, $f=\mu N=\mu mg$

$F-\mu mg=ma\\\\a=\dfrac{F-\mu mg}{m}\\\\a=\dfrac{750-0.12\times 250\times 9.8}{250}\\\\a=1.82\ m/s^2$

So, the acceleration of the crate is $1.82\ m/s^2$ . Hence, this is the required solution.

4 0

3 years ago