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4 years ago

Which compares the thermal energy found in a piece of coal with the thermal energy found in a newly opened coal mine?

1 answer:

4 0

<span>The thermal energy found in a piece of coal is lesser than in the thermal energy in a newly opened coal mine. The newly opened coal mine requires a greater thermal energy to really open it due to its solid structure. Whereas in a piece of coal, it only requires a lesser amount of thermal energy to extract it.</span>

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A satellite has a mass of 5850 kg and is in a circular orbit 4.1 x10 to the 5th power m above the surface of a planet. The perio

koban [17]

Answer:

W = 24.28 kN

Explanation:

given,

Mass of satellite = 5850 Kg

height , h = 4.1 x 10⁵ m

Radius of planet = 4.15 x 10⁶ m

Time period = 2 h

= 2 x 3600 = 7200 s

Time period of satellite

$T = \dfrac{2\pi}{R}\sqrt{\dfrac{(R+h)^3}{g}}$

R is the radius of planet

h is the height of satellite

$T^2 = \dfrac{4\pi^2}{R^2}\ {\dfrac{(R+h)^3}{g}}$

now calculation of acceleration due to gravity

$g = \dfrac{4\pi^2}{R^2}\ {\dfrac{(R+h)^3}{T^2}}$

$g = \dfrac{4\pi^2}{(4.15\times 10^6)^2}\ {\dfrac{(4.15\times 10^6+4.1\times 10^5)^3}{(7200)^2}}$

g = 4.15 m/s²

True weight of satellite

W = m g

W = 5850 x 4.15

W = 24277.5 N

W = 24.28 kN

True weight of the satellite is W = 24.28 kN

8 0

3 years ago

Serena is a research student who has conducted an experiment on the discoloration of marble. Read about Serena’s experiment. The

agasfer [191]

She did not have a control group, and she did not expose all three samples to wind. Because her hypothesis was a combination of things, she needed to test the different combinations.
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7 0

4 years ago

Read 2 more answers

If the period of a spring is 5 seconds what is the frequency

Scilla [17]

Answer:

C. 0.2 Hertz

Explanation:

The frequency of a spring is equal to the reciprocal of the period:

$f=\frac{1}{T}$

where

f is the frequency

T is the period

For the spring in this problem,

T = 5 s

therefore, the frequency is

$f=\frac{1}{5 s}=0.2 Hz$

7 0

3 years ago

An isolated conducting sphere has a 12 cm radius. One wire carries a current of 1.0000049 A into it while another wire carries a

tatuchka [14]

Answer:

it will take for the sphere to increase in potential by 1500 V, 503.71 s.

Explanation:

The charge on the sphere after t seconds is:

q = (1.0000049 - 1.0000000) t = 0.0000049 t

The voltage on the surface is

V = k * $\frac{q}{R}$ = k 0.0000049 t / R

solve for t

t = (R*V) / (0.0000049 k) = (0.12 * 1500) / (0.0000049 * $9e^{9}$ ) = 503.71 s

7 0

4 years ago

Christine Ladd-Franklin was a mathematician and psychologist who faced many obstacles as a woman, but she persevered and made si

Veseljchak [2.6K]

The struggles were that women weren't really supposed to get an education back then, people called intelligent women witches and wouldn't teach them things. Those were the main struggles. As for her contributions to psychology, check this site out, https://en.wikipedia.org/wiki/Christine_Ladd-Franklin

7 0

3 years ago