Answer:
c)They can also be simultaneous in S if their separation is zero.
Explanation:
By relativity theory, we can say two events when seen from two different reference frames can only be simultaneous when they are at the same space location and occur simultaneously in at least one reference frame, therefore when Frame S′ usually passes Frame S. Two occurrences in S′ are simultaneous, therefore these occurrences can be simultaneous in S when their separation is 0 (that is they are at the same location)
And therefore option c. If their separation is zero, they can also be simultaneous in S.
Answer:
heya answer option b
Explanation:
please mark me brainliest
<span>During the reading of a blueprint, a general tolerance
pertains to all dimensions that are not independently identified. All tolerances
are +\- .030. General tolerances are mostly found in the blueprint’s set of
information. Let’s say for example, a compact tolerance is required, then a
specific tolerance is considered for specific areas of the blueprint. These
kinds of tolerances are commonly found along the affected area.</span>
Answer:
E = 1.655 x 10⁷ N/C towards the filament
Explanation:
Electric field due to a line charge is given by the expression
E = ![[tex]\frac{\lambda}{2\pi\times\epsilon_0\times r}](https://tex.z-dn.net/?f=%5Btex%5D%5Cfrac%7B%5Clambda%7D%7B2%5Cpi%5Ctimes%5Cepsilon_0%5Ctimes%20r%7D)
[/tex]
where λ is linear charge density of line charge , r is distance of given point from line charge and ε₀ is a constant called permittivity and whose value is
8.85 x 10⁻¹².
Putting the given values in the equation given above
E = 
E = 1.655 x 10⁷ N/C
Virtual upright and the same size
