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Anvisha [2.4K]
3 years ago
5

a soccer player kicks a ball. According to Newton's third law of motion, the player's foot exerts a force on the ball. The ball

exerts a force on the foot. Why don't the forces cancel out to result in a net force of zero?​
Physics
1 answer:
Leto [7]3 years ago
8 0

Answer:

The forces are exerted on different objects so they are not balanced forces.

Explanation:

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2. A bus drove 8 meters East, then turned to drive 8 meters North, then 2 meters
Sphinxa [80]

Answer:

Long question good luck:)

Explanation:

3 0
3 years ago
What is the difference between the law of conservation of energy and conserving energy
babymother [125]
<span>law of conservation of </span>energy<span> is </span><span><span>states that energy of the universe remains constant cant be created nor destroyed and conserving energy is not using as much power as you was like trying to make power bill lower while law of conservation is constant </span> </span>


6 0
3 years ago
What allows the bimetallic coil to turn on or off a heating or cooling system? The two metals contract the same amount. The ther
Vedmedyk [2.9K]

Answer:

The two metals expand differently.

Explanation:

The bimetallic strip has two metal strips positioned like a bridge, these strips connect the electrical circuit to the heating system. When these strips are linear or "down" they allow the electricity to move through the circuit to the heating system to turn the heat on. When the strips are "up" the disconnect the electricity flow, thus turning the heating system off, thus the room becomes cool/cold.

3 0
3 years ago
What are the units, if any, of the particle in a box wavefunction. What does this mean?
SIZIF [17.4K]

Answer:

  • [\psi]= [Length^{-3/2}]
  • This means that the integral of the square modulus over the space is dimensionless.

Explanation:

We know that the square modulus of the wavefunction integrated over a volume gives us the probability of finding the particle in that volume. So the result of the integral

\int\limits^{x_f}_{x_0} \int\limits^{yf}_{y_0} \int\limits^{z_f}_{z_0} |\psi|^2 \, dz \,  dy \,  dx

must be dimensionless, as represents a probability.

As the differentials has units of length

[dx]=[dy]=[dz]=[Length]

for the integral to be dimensionless, the units of the square modulus of the wavefunction has to be:

[\psi]^2 = [Length^{-3}]

taking the square root this gives us :

[\psi] = [Length^{-3/2}]

5 0
3 years ago
The weight of a standard object defined as having a mass of exactly 2.9 kg is measured to be 28.449 n. in the same laboratory, a
PtichkaEL [24]
Mass of the object m = 2.9 kg 
Force F1 = 28.449 N 
F1 = m1 x a => a = F / m => 28.449 / 2.9 => a = 9.81, which is gravitational acceleration. 
In the same lab, a = g = 9.81, second object F2 = 48.7N = m2 x a 
m2 = F2 / a => 48.7 / 9.81 => m2 = 4.96 kg 
Mass of the second object m2 = 4.96 kg
4 0
3 years ago
Read 2 more answers
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