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Nikolay [14]
3 years ago
15

A new community organization has 12 members. In how many ways can it elect a president, a vice president, and a secretary from a

mong its members if no member may hold more than one office?
Mathematics
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

The number of ways he can elect the president,the vice President and the secretary is 1320 ways

Step-by-step explanation:

This is a permutation question.

Any of the 12 members can be the President , when this is done, any of the remaining 11 can be the vice president ,when this is done, any of the remaining 10 can be the secretary.

The required number of ways is;

12*11*10= 1320ways

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Given: sin(18m-12)=cos(7m+2), find the value of m.
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Answer:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

Step-by-step explanation:

Solve for m:

-cos(7 m + 2) sin(12 - 18 m) = 0

Multiply both sides by -1:

cos(7 m + 2) sin(12 - 18 m) = 0

Split into two equations:

cos(7 m + 2) = 0 or sin(12 - 18 m) = 0

Take the inverse cosine of both sides:

7 m + 2 = π n_1 + π/2 for n_1 element Z

or sin(12 - 18 m) = 0

Subtract 2 from both sides:

7 m = -2 + π/2 + π n_1 for n_1 element Z

or sin(12 - 18 m) = 0

Divide both sides by 7:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or sin(12 - 18 m) = 0

Take the inverse sine of both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or 12 - 18 m = π n_2 for n_2 element Z

Subtract 12 from both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or -18 m = π n_2 - 12 for n_2 element Z

Divide both sides by -18:

Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

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