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4 years ago

As a result of the violent revolts in france in july 1830

Physics

1 answer:

Ede4ka [16]4 years ago

4 0

Answer:

As a result of the violent revolts in france in july 1830 gave up the throne and fled for Great Britain.

Explanation:

Following Charles X taking the throne of France, he strengthened the power of the clergy and the monarchy. In 1830, Charles X attempted to suppress the Constitution, suspend Parliament, and shut down the press. The press disobeyed and encouraged mobs to protest. The protests got violent and fearing for his life, Charles X stepped down from the throne and took his family to Great Britain.

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A motor does 8000j of work in 20 seconds. What is the power of the motor

lozanna [386]

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3 years ago

A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 35.5 m/s. a) What is the coeff

postnew [5]

Answer:

The coefficient of friction present between the roadway and the wheels of the truck is <u>0.833</u>.

Explanation:

Given:

Radius of the curve (R) = 150 m

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Let the coefficient of friction between the roadway and the wheels of the truck be "μ".

As the truck is moving around a circular curve. So, the force acting on it is centripetal force which acts in the radial inward direction towards the center of the circular curve.

The centripetal force acting on the truck is given as:

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Now, the friction between the roadway and the wheels of the truck is responsible for providing the necessary centripetal force. So, frictional force is equal to the centripetal force necessary for circular motion.

Frictional force is given as:

$f=\mu N$

Where, 'N' is the normal force. Since there is no vertical motion, the normal force is equal to weight of truck. So,

$N=mg$

Therefore, frictional force, $f=\mu mg$

Now, frictional force = centripetal force

$f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu = \frac{v^2}{Rg}$

Plug in the given values and solve for 'μ'. This gives,

$\mu=\frac{(35\ m/s)^2}{(150\ m)(9.8\ m/s^2)}\\\\\mu=\frac{1225\ m^2/s^2}{1470\ m^2/s^2}\\\\\mu=0.833$

Therefore, the coefficient of friction present between the roadway and the wheels of the truck is 0.833

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Serhud [2]

Answer:

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