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strojnjashka [21]
3 years ago
8

A dog travels 3m East and then 4m West, what is his displacement?

Physics
1 answer:
RideAnS [48]3 years ago
8 0

Answer:

his displacement is 5m

Explanation:

A is the stage at which a man starts walking. He's walking 4 m north, i.e. AB, then going 3 m east, i.e. BC. The displacement is the connecting straight line between the original and the final position. The displacement is thus the AC hypotenuse of the right-angle triangle. By applying the theorem of hypotenuse, we get  

⇒displacement=16+9−−−−−√=25−−√=5m

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A uniform electric field of magnitude 7.0 ✕ 104 N/C passes through the plane of a square sheet with sides 5.0 m long. Calculate
Vadim26 [7]

Answer:

1.52*10^6 Nm^2/C

Explanation:

Given that:

Electrical field E = 7.0 * 10^{-4}N/C

square side l = 5.0 m

Area A = 5.0 * 5.0

= 25.0 m²

Angle ( θ ) between area vector and E = (90° - 60°)

= 30°

The flux \phi_E can now be determined by using the expression

\phi_E = E*A*Cos \theta

\phi_E = 7.0 * 10^{-4}N/C *25.0m*Cos 30^0

\phi_E = 1515544.457 Nm^2/C

\phi_E = 1.52*10^6 Nm^2/C

5 0
3 years ago
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compare to visible light, the wavelength of x-rays is shorter longer or the same and the frequency is lower higher or the same
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Answer:shorter higher

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7 0
3 years ago
You drop a ball from a window located on an upper floor of a building. It strikes the ground with speed v. You now repeat the dr
bulgar [2K]

Answer:

 y = y₀ (1 - ½ g y₀ / v²)

Explanation:

This is a free fall problem. Let's start with the ball that is released from the window, with initial velocity vo = 0 and a height of the window i

          y = y₀ + v₀ t - ½ g t²

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for the ball thrown from the ground with initial velocity v₀₂ = v

         y₂ = y₀₂ + v₀₂ t - ½ g t²

     

in this case y₀ = 0

         y₂2 = v t - ½ g t²

at the point where the two balls meet, they have the same height

         y = y₂

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         y₀i = v t

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since we have the time it takes to reach the point, we can substitute in either of the two equations to find the height

         y = y₀ - ½ g t²

         y = y₀ - ½ g (y₀ / v)²

         y = y₀ - ½ g y₀² / v²

        y = y₀ (1 - ½ g y₀ / v²)

with this expression we can find the meeting point of the two balls

6 0
4 years ago
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Explanation:

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