A dog travels 3m East and then 4m West, what is his displacement?

Physics

1 answer:

RideAnS [48]2 years ago

8 0

Answer:

his displacement is 5m

Explanation:

A is the stage at which a man starts walking. He's walking 4 m north, i.e. AB, then going 3 m east, i.e. BC. The displacement is the connecting straight line between the original and the final position. The displacement is thus the AC hypotenuse of the right-angle triangle. By applying the theorem of hypotenuse, we get

⇒displacement=16+9−−−−−√=25−−√=5m

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A pilot flies in a straight path for 1 h 30 min. She then makes a course correction, heading 10 degrees to the right of her orig

r-ruslan [8.4K]

Answer:

2406 miles

Explanation:

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$\angle ABC =(180-10) \textdegree=170\textdegree$

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$c=690x1.5\\=1035mi$

#Distance traveled in next two hrs:

$a=690\times 2\\=1380mi$

#Now using the Cosine Rule:

$b^2=a^2+c^2-2ab\cos B\\\\=1380^2+1035^2-2(1380)(1035)cos170\textdegree\\\\b^2=5788.83\\\\b\approx 2406.00 \ mi$

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4 0

3 years ago

Consider that a ray of light is travelling from glass to water. The refractive index of water is 1.30 (i e n . ., 1.30 w = ) and

Bess [88]

Answer:

$\theta_i=49.88^{\circ}$

Explanation:

Total internal reflection can happen when light goes from a medium with higher refractive index (in this case, glass) to a medium with lower refractive index (in this case, water).

Snell's Law tells us that $n_isin\theta_i=n_rsin\theta_r$ , where the i stands for incident (in this case, glass) and the r for refracted (in this case, water). We want to know when $\theta_r=90^{\circ}$ , that is, when $n_isin\theta_i=n_r$ , and this happens when the incident angle is: