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3 years ago

A dog travels 3m East and then 4m West, what is his displacement?

Physics

1 answer:

RideAnS [48]3 years ago

8 0

Answer:

his displacement is 5m

Explanation:

A is the stage at which a man starts walking. He's walking 4 m north, i.e. AB, then going 3 m east, i.e. BC. The displacement is the connecting straight line between the original and the final position. The displacement is thus the AC hypotenuse of the right-angle triangle. By applying the theorem of hypotenuse, we get

⇒displacement=16+9−−−−−√=25−−√=5m

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A 3.0-kg block starts at rest at the top of a 37° incline, which is 5.0 m long. Its speed when it reaches the bottom is 2.0 m/s.

Mama L [17]

Answer: $f_{r}$ = 16.49N

Explanation: The object is placed on an inclined plane at an angle of 37° thus making it weight have two component,

$W_{x}$ = horizontal component of the weight = mgsinФ

$W_{y}$ = vertical component of weight = mgcosФ

Due to the way the object is positioned, the horizontal component of force will accelerate the object thus acting as an applied force.

by using newton's law of motion, we have that

mgsinФ - $f_{r}$ = ma

where m = mass of object=5kg

a = acceleration= unknown

Ф = angle of inclination = 37°

g = acceleration due to gravity = 9.8 $m/s^{2}$

$f_{r}$ = frictional force = unknown

we need to first get the acceleration before the frictional force which is gotten by using the equation below

$v^{2} = u^{2} + 2aS$

where v = final velocity = 2m/s

u = initial velocity = 0m/s (because the object started from rest)

a= unknown

S= distance covered = length of plane = 5m

$2^{2} = 0^{2} + 2*a*5\\\\4= 10 *a\\\\a = \frac{4}{10} \\a = 0.4m/s^{2}$

we slot in a into the equation below to get frictional force

mgsinФ - $f_{r}$ = ma

3 * 9.8 * sin 37 - $f_{r}$ = 3* 0.4

17.9633 - $f_{r}$ = 1.2

$f_{r}$ = 17.9633 - 1.2

$f_{r}$ = 16.49N

4 0

4 years ago

What is the decibel level of the noise in a typical classroom?

maks197457 [2]

I think it is 100 dB .I holp it is help.

6 0

3 years ago

Read 2 more answers

Give an example of how a bicycle rider would accelerate? Explain the three different ways a bicyclist could

Ostrovityanka [42]

A cyclist can increase the speed of their bike in various ways such as, changing gears, positioning themselves properly, increase the pedalling rate

<h3>Ways in which a cyclist can increase the speed of a bicycle</h3>

Bicycle riders could accelerate/ increase their speed in various ways

By Changing the gears and by doing so increasing the speed
By Positioning themselves in a streamlined manner, this is so that they become aerodynamic hence they cut across airflow.
By increase the rate at which they are pedalling the bicycle.

Learn more about increasing bicycle speed here:

brainly.com/question/13749553

7 0

3 years ago

A car which is traveling at a velocity of 1.6 m/s undergoes an acceleration of 9.2 m/s over a distance of 540 m. How fast is it

mixas84 [53]

Answer:

Vf = 99.7 m/s

Explanation:

In order to find the final velocity of the car, we will use the third equation of motion. The third equation of motion is given as follows:

$2as = V_{f}^{2} - V_{i}^{2}$

where,

a = acceleration of the car = 9.2 m/s²

s = distance traveled by the car = 540 m

Vf = Final Speed of the car = ?

Vi = Initial Speed of the car 1.6 m/s

$2(9.2\ m/s^{2})(540\ m) = (V_{f})^{2}-(1.6\ m/s)^{2}\\V_{f}^{2} = 9936\ m^{2}/s^{2} + 2.56\ m^{2}/s^{2}\\\\V_{f} = \sqrt{9938.56\ m^{2}/s^{2}}$

8 0

3 years ago

A projectile travels above level ground. The initial vertical component of its velocity is 0.90 m/s and the initial horizontal c

sladkih [1.3K]

<span>at maximum height the final velocity will be 0
using v=u+at and resolving vertically we get
v=0.6+(-9.81)t
v=0.6-9.81t
0=0.6-9.81t
9.81t=0.6
t=0.6/9.81
t=0.061 to 3sf

Now we need to resolve horizontally to find the horizontal distance
using s=ut+1/2at^2
However we now need the total time taken for the projectile travel and return to the ground. We can assume the time taken for the projectile to reach its maximum height and return to the ground is the same therefore
the total time is 2 x 0.061=0.122seconds. They'll be now horizontal acceleration in this case scenario therefore

Hence s=ut+1/2at^2
since a=0
s=ut
s=0.6 x 0.122
s=0.073m
</span>

5 0

3 years ago