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ludmilkaskok [199]
3 years ago
13

The existence of the dwarf planet Pluto was proposed based on irregularities in Neptune's orbit. Pluto was subsequently discover

ed near its predicted position. But it now appears that the discovery was fortuitous, since Pluto is small and the irregularities in Neptune's orbit were not well known. Answer the following to illustrate that Pluto has a minor effect on the orbit of Neptune compared with other planets. (a) Calculate the acceleration of gravity at Neptune due to Pluto when they are 3.2 1012 m apart. The mass of Pluto is 1.3 1022 kg. g1 = m/s2 (b) Calculate the acceleration of gravity at Neptune due to Uranus, when they are 3.2 1012 m apart. The mass of Uranus is 8.68 1025 kg. g2 = m/s2 (c) Give the ratio of this acceleration to that due to Pluto. g2 g1 =
Physics
1 answer:
iris [78.8K]3 years ago
3 0

Answer:

a) g1 = 8.467 10⁻¹⁴ m / s² , b)  g2 = 5.65 10⁻¹⁰ m / s² , c) g2 / g1 = 6.6 10³

Explanation:

a) for this we will use Newton's second law where force is the force of universal gravitation

         F = m a

        G m M / r² = m a

        a = g = G M / r²

By the effect of Pluto

        g1 = 6.67 10⁻¹¹  1.3 10²² / (3.2 10¹²)²

        g1 = 8.467 10⁻¹⁴ m / s²

b) By the effect of Uranus

        g2 = 6.67 10⁻¹¹ 8.68 10²⁵ / (3.2 10¹²)²

        g2 = 5.65 10⁻¹⁰ m / s²

c) the relationship between these accelerations

        g2 / g1 = 5.65 10⁻¹⁰ / 8.47 10⁻¹⁴

        g2 / g1 = 0.66 10⁴

        g2 / g1 = 6.6 10³

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If you increase the elasticity of a material, what happens to the speed of a mechanical wave going through it?
Sophie [7]

Answer:

At the molecular level, materials are held together by bonds, which act like springs for small displacements from the equilibrium spacing between neighboring atoms. Push the atoms close, the bond pushes back to keep them apart. Pull them apart, the bond pulls the atoms closer. For those small displacements, it acts like a spring

The speed of the wave will be related to the stiffness of of those springs - you compress the material - how quickly do all of those little springs rebound and push their neighboring atoms away, sending that wave of compression through the material.

Explanation:

5 0
2 years ago
Recall that the blocks can only move along the x axis. the x components of their velocities at a certain moment are v1x and v2x.
Contact [7]
The center of mass is given with this formula:
x_c=\frac{\sum_{n=1}^{n=i}m_ix_i}{M}
Velocity is:
v=\frac{dv}{dt}
So, for the velocity of the center of mass we have:
\frac{dx_c}{dt}=\frac{\sum_{n=1}^{n=i}d(m_ix_i)}{Mdt}\\
v_c=\frac{\sum_{n=1}^{n=i}p_i}{M}\\
In our case it is:
v_{xc}=\frac{m_1v_{x1}+m_2v_{x2}}{m_1+m_2}
 
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3 years ago
The uniform rods AB and BC weigh 24 ky and kg, respectively,and the small wheel at C is of negligible weight. If the wheel ismov
victus00 [196]

The velocity of pin B after rod AB has rotated through 90* is vb = 3.2549 m/s.

<h3>What is Potential and Kinetic energy?</h3>

Potential energy is the energy that is stored in any item or system as a result of its location or component arrangement. The environment outside of the object or system, such as air or height, has no impact on it. In contrast, kinetic energy refers to the energy of moving particles inside a system or an item.

mass of rod, mab = 2.4kg

mass of rod, mbc = 4kg

conservation of energy

T_{1}  + V_{1} = T_{2}  + V_{2}

h_{ab}  = h_{bc}  = 0.18m

potential energy at position 1,

V1 = m_{ab} gh_{ab}  + m_{bc} gh_{bc}

V1 = 2.5 * 9.81 * 0.18 + 4 * 9.81 * 0.18

V1 = 11.30112

kinetic energy T1 at position 1 is zero

potential energy at position 2 is zero

K.E at position 2,

T_{2} = \frac{1}{2} l_{ab} w^{2}_{ab} +  \frac{1}{2} m_{bc} v^{2}_{G} +  \frac{1}{2} lw^{2}_{bc}

l_{ab} =\frac{m_{ab} l^{2}_{ab}  }{3}

= 1/3 *4 * (0.36)²

=0.10368kg m²

l =\frac{m_{bc} l^{2}_{bc}  }{12}

= 1/12 *4 * (0.6)²

=0.12kg m²

on putting the values in above equation we get,

T₂ = 1.0667vb²

0 + 11.30112 = 1.0667vb² + 0

vb = 3.2549 m/s

to learn more about Kinetic and potential energy go to - brainly.com/question/18963960

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5 0
1 year ago
A 5.67-kg block of wood is attached to a spring with a spring constant of 150 N/m. The block is free to slide on a horizontal fr
nikklg [1K]

Answer:

v=0.94 m/s

Explanation:

Given that

M= 5.67 kg

k= 150 N/m

m=1 kg

μ = 0.45

The maximum acceleration of upper block can be μ g.

 a= μ g                          ( g = 10 m/s²)

The maximum acceleration of system will ω²X.

ω = natural frequency

X=maximum displacement

For top stop slipping

μ g  =ω²X

We know for spring mass system natural frequency given as

\omega=\sqrt{\dfrac{k}{M+m}}

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\omega=\sqrt{\dfrac{150}{5.67+1}}

ω = 4.47 rad/s

μ g  =ω²X

By putting the values

0.45 x 10 = 4.47² X

X = 0.2 m

From energy conservation

\dfrac{1}{2}kX^2=\dfrac{1}{2}(m+M)v^2

kX^2=(m+M)v^2

150 x 0.2²=6.67 v²

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This is the maximum speed of system.

7 0
2 years ago
Read 2 more answers
What is energy converted to if it is not used to do work?
Romashka [77]

Answer:

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Explanation:

3 0
2 years ago
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