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ludmilkaskok [199]
3 years ago
13

The existence of the dwarf planet Pluto was proposed based on irregularities in Neptune's orbit. Pluto was subsequently discover

ed near its predicted position. But it now appears that the discovery was fortuitous, since Pluto is small and the irregularities in Neptune's orbit were not well known. Answer the following to illustrate that Pluto has a minor effect on the orbit of Neptune compared with other planets. (a) Calculate the acceleration of gravity at Neptune due to Pluto when they are 3.2 1012 m apart. The mass of Pluto is 1.3 1022 kg. g1 = m/s2 (b) Calculate the acceleration of gravity at Neptune due to Uranus, when they are 3.2 1012 m apart. The mass of Uranus is 8.68 1025 kg. g2 = m/s2 (c) Give the ratio of this acceleration to that due to Pluto. g2 g1 =
Physics
1 answer:
iris [78.8K]3 years ago
3 0

Answer:

a) g1 = 8.467 10⁻¹⁴ m / s² , b)  g2 = 5.65 10⁻¹⁰ m / s² , c) g2 / g1 = 6.6 10³

Explanation:

a) for this we will use Newton's second law where force is the force of universal gravitation

         F = m a

        G m M / r² = m a

        a = g = G M / r²

By the effect of Pluto

        g1 = 6.67 10⁻¹¹  1.3 10²² / (3.2 10¹²)²

        g1 = 8.467 10⁻¹⁴ m / s²

b) By the effect of Uranus

        g2 = 6.67 10⁻¹¹ 8.68 10²⁵ / (3.2 10¹²)²

        g2 = 5.65 10⁻¹⁰ m / s²

c) the relationship between these accelerations

        g2 / g1 = 5.65 10⁻¹⁰ / 8.47 10⁻¹⁴

        g2 / g1 = 0.66 10⁴

        g2 / g1 = 6.6 10³

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A 970-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are locked,
vlabodo [156]

Answer:

22.73 m/s or 81.72 kph

Explanation

We can find the combined mass of both cars as

970 kg + 2300 kg = 3270 kg.

Then the normal force of the cars can be calculated as

F(n)= mg

Where g is acceleration due to gravity 9.8m/s^2

3270 kg ×9.8 = 32046 kg*m/s^2.

coefficient of kinetic friction between tires and road to be 0.80 × F(n)

Then the frictional force can be calculated as

= (32046kg*m/s^2 × 0.80 )

= 25636.8 kg*m/s^2

We can now calculate the work done that was used stopping the cars as

Frictional force × distance

(25636.8 kg*m/s^2 ) × 2.9m= 74346.72kg*m^2/s^2

From kinetic energy formula, the combined velocity of the car can be determined

E=0.5 M V²

√(2E/M) = V

√(2*74346.72kg*m^2/s^2 / 3270 kg) = V

V= √ (45.472)

V=6.743293m/s

the momentum of both cars can be determined as

6.743293m/s * 3270 kg

= 22050.57kg*m/s

Now the final momentum of both cars must be equal to the the momentum of

the sports car just prior to the collision. Therefore, the speed of the sports car at impact.

=(22050.57 kg*m/s) / 970 kg = 22.73 m/s

We can convert that to km/h.

22.73 m/s * 3600 s/h / 1000 m/km = 81.72 kph

7 0
3 years ago
Using the periodic table, choose the more reactive nonmetal.<br> Si or N
tatiyna

Answer:

N

Explanation:

Nitrogen

3 0
3 years ago
Two Carnot air conditioners, A and B, are removing heat from different rooms. The outside temperature is the same for both rooms
amid [387]

Answer:

a) Work required for air conditioner A = 354.7 J

b) Work required for air conditioner B = 310.3 J

c) The magnitude of the heat deposited outside for conditioner A = 4684.7 J

d) The magnitude of the heat deposited outside for conditioner B = 4640.3 J

Explanation:

In a carnot air conditioner, it operates like a reverse carnot engine; i.e. it removes heat from the cold reservoir (making it colder) and dumps the heat in the hot reservoir (making it hotter)

For a Carnot air conditioner,

Q꜀ is the heat removed from the colder reservoir = 4330 J for both cases

T꜀ is the temperature of the colder reservoir (temperature of the rooms) = 293 K and 296 K for both cases to be considered.

Qₕ is the heat deposited in the warmer reservoir = ? for both cases

Tₕ is the temperature of the hot reservoir (temperature of outside) = 317 K for both cases.

For Carnot air conditioners,

Qₕ = W + Q꜀ (eqn 1)

And

(Qₕ/Tₕ) - (Q꜀/T꜀) = 0 (eqn 2)

Making Qₕ the subject of formula in eqn 2

Qₕ = Tₕ (Q꜀/T꜀)

Substituting this into eqn 1

Tₕ (Q꜀/T꜀) = W + Q꜀

Q꜀ (Tₕ/T꜀) - Q꜀ = W

Q꜀ [(Tₕ - T꜀)/T꜀ ] = W

W = Q꜀ [ (Tₕ - T꜀)/T꜀ ]

For the air conditioner A,

T꜀ = 293 K, Tₕ = 317 K, Q꜀ = 4330 J, W = ?

W = Q꜀ [ (Tₕ - T꜀)/T꜀ ] = 4330 [ (317 - 293)/293] = 354.7 J

For the air conditioner B,

T꜀ = 296 K, Tₕ = 317 K, Q꜀ = 4330 J, W = ?

W = Q꜀ [ (Tₕ - T꜀)/T꜀ ] = 4330 [ (317 - 296)/296] = 310.3 J

c) Qₕ = W + Q꜀

For conditioner A,

Qₕ = 354.7 + 4330 = 4684.7 J

For conditioner B,

Qₕ = 310.3 + 4330 = 4640.3 J

8 0
3 years ago
ASAP ASAP ASAP
mylen [45]

The experiments will involve two billiard balls of known masses, m₁ and m₂, and velocities u₁ and u₂. The two are allowed to collide and the velocities of the balls after the collision v₁ and v₂ are recorded.

The momentum before and after the collision is then calculated as follows:

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

<h3>What is the statement of the law of conservation of momentum?</h3>

The law of the conservation of momentum states that the momentum before and after collision in a system of colliding bodies is conserved

The momentum of a body is calculated using the formula below:

Momentum = mass * velocity.

Hence, for the two billiard balls, the momentum before and after the collision is conserved.

Learn more about momentum at: brainly.com/question/1042017

#SPJ1

3 0
1 year ago
The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of t
zysi [14]

Answer:

Explanation:

Speed of electrical nerve signal = 33 m /s

Distance travelled = 1.3 m

time taken = distance / speed

= 1.3 / 33  

= .039 s

= 39 ms ( millisecond )  .

3 0
3 years ago
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