AWSER is C
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Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1
Let us consider the common ratio to be ‘x’.
So, toy blocks with alphabet A is 4x and
toy blocks with alphabet B is 7x and
toy blocks with alphabet C is 3x and
toy blocks with alphabet D is x
Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.
As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.
So,
4x=50 + 3x
x=50
Thus, the number of ‘B’ blocks is 7x = 7(50) = 350
350 is the required number.
Answer:
8 - 2π square units.
π/16 - 1/8 square units.
6π - 9√3 square units.
Step-by-step explanation:
The area of the square = 2√2 * 2√2
= 2*2*2
= 8.
The area of the circle = πr^2
= π * [ ( 2√2)/ 2) ]^2
= π (√2)^2
= 2π.
Second Question:
The area of the circle = π(1/2)^2 = π/4.
Finding the area of the square:
1^2 = 2x^2
x^2 = 1/2
So the area of the square = 1/2
So the area of the red part = 1/4 ( π/4 - 1/2).
= π/16 - 1/8.
Third question
Area of the circle = 6^2 * π = 36π.
Now 60 degrees is 1/6 of 360 degrees so the are of the sector is 6π.
The area of the segment = 6π - 0.5 * 6^2 sin 60
= 6π - 18√3/2
= 6π - 9√3 square units.
The answer is .1391
Hope this helps!
(If your confused, I just put this in a calculator)
Answer:
1) 1/6, 1/3, 1/2, 3/4
2) 3/10, 2/5, 7/10, 4/5
3) 1/4. 7/12. 2/3, 5/6
4) 4/15. 11/30, 2/5, 7/10
Step-by-step explanation: Either convert all in a set to a common denominator, or convert to decimal fractions.
