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marin [14]
3 years ago
8

Helpppppp helpppppp helppppp​

Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
7 0

where is the diagram?

without the diagram i can't help

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What would the expected temperature change be (in Fahrenheit) ida 0.5 gran sample of water released 50.1 J of heat energy? The s
Mariana [72]
<h3>Answer:</h3>

23.95 °C

<h3>Explanation:</h3>

We are given;

  • Mass of the sample is 0.5 gram
  • Quantity of heat released as 50.1 Joules
  • Specific heat capacity is 4.184 J/g°C

We are required to calculate the change in temperature;

  • Quantity of heat absorbed is given by the formula;
  • Q = mass × specific heat capacity × Change in temperature

That is, Q = mcΔT

Rearranging the formula;

ΔT = Q ÷ mc

Therefore;

ΔT = 50.1 J ÷ (0.5 g × 4.184 J/g°C)

    = 23.95 °C

Therefore, the expected change in temperature is 23.95 °C

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Picture credit - Google images

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4 years ago
What is the reason why carbonated beverages be kept cold?
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Option A) Decreased temperature keeps gases like carbon dioxide dissolved.

Carbonation is made with CO2 which is also know as liquid carbonic. The low temperature favors higher solubility of CO2 in water
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A motorcycle travels 817 meters in 19 seconds. what is its average speed?
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