<h3>
Answer:</h3>
23.95 °C
<h3>
Explanation:</h3>
We are given;
- Mass of the sample is 0.5 gram
- Quantity of heat released as 50.1 Joules
- Specific heat capacity is 4.184 J/g°C
We are required to calculate the change in temperature;
- Quantity of heat absorbed is given by the formula;
- Q = mass × specific heat capacity × Change in temperature
That is, Q = mcΔT
Rearranging the formula;
ΔT = Q ÷ mc
Therefore;
ΔT = 50.1 J ÷ (0.5 g × 4.184 J/g°C)
= 23.95 °C
Therefore, the expected change in temperature is 23.95 °C
<span>Alkaline Earths hope this helps
</span>
Picture credit - Google images
whenever you have problem for ph and poh just make this table and go from there .
Ph = 14 - Poh
Poh = 14- Ph
Option A) Decreased temperature keeps gases like carbon dioxide dissolved.
Carbonation is made with CO2 which is also know as liquid carbonic. The low temperature favors higher solubility of CO2 in water
Speed = distance/time
=> speed = 817/19 m/sec = 43 m/sec
hope it helps!
