3 years ago

Why should you clean up after every investigation

Chemistry

2 answers:

ella [17]3 years ago

8 0

<span>Why should you clean up after every investigation?

Simple, it is for safety ....and a clean classroom/lab</span>

8_murik_8 [283]3 years ago

6 0

You should clean up after every investigation because if you leave a mess, maybe another detective will come in and get lost because of the mess you left.

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2 years ago

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24 CO2 (g) + 26 H2O (i ) + 15,026 kJ - 2 C12H26 (i ) + 37 O2 (g) ?<br><br> Endothermic or exothermic

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2 years ago

If aluminum has a density of 2.7 g/cm³, what is the volume of 2.7 grams of aluminum?

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1 year ago

Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp

gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

$ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})$

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in j/mol R Ea is

Ea=35.5*1000 j/mol R

$ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492$

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}