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3 years ago

Why should you clean up after every investigation

Chemistry

2 answers:

ella [17]3 years ago

8 0

<span>Why should you clean up after every investigation?

Simple, it is for safety ....and a clean classroom/lab</span>

8_murik_8 [283]3 years ago

6 0

You should clean up after every investigation because if you leave a mess, maybe another detective will come in and get lost because of the mess you left.

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Under the same conditions of temperature and pressure a liquid differs from a gas because the particles of the liquid

noname [10]

Answer:

liquid has more attraction between molecules. It takes energy to break these forces to change the liquid to a gas.

Explanation:

because liquid has more attraction

6 0

3 years ago

Read 2 more answers

Which method is suitable for collection a a<br>carbon dioxide.Explain

mel-nik [20]

Answer:

Carbon dioxide can be collected over water. Carbon dioxide is slightly soluble in water and denser than air, so another way to collect it is in a dry, upright gas jar.

Explanation:

8 0

3 years ago

If the pressure on a gas sample is tripled and the absolute temperature is quadrupled, by what factor will the volume of the sam

antoniya [11.8K]

Answer:

b. 4/3

Explanation:

Given data

Initial pressure: P₁

Initial volume: V₁

Initial temperature: T₁

Final pressure: P₂ = 3 P₁

Final volume: V₂

Final temperature: T₂ = 4 T₁

We can find by what factor will the volume of the sample change using the combined gas law.

$\frac{P_{1}.V_{1}}{T_{1}} =\frac{P_{2}.V_{2}}{T_{2}}\\\frac{P_{1}.V_{1}}{T_{1}} =\frac{3P_{1}.V_{2}}{4T_{1}}\\V_{1} =\frac{3V_{2}}{4}\\V_{2}=4/3 V_{1}$

7 0

3 years ago

The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate

Nimfa-mama [501]

Answer:

lattice parameter = 5.3355x10^-8 cm

atomic radius = 2.3103x10^-8 cm

Explanation:

known data:

p=0.855 g/cm^3

atomic mass = 39.09 g/mol

atoms/cell = 2 atoms

Avogadro number = 6.02x10^23 atom/mol

a) the lattice parameter:

Since potassium has a cubic structure, its volume is equal to:

v = [(atoms/cell)x(atomic mass)/(p)x(Avogadro number)]

substituting values:

v =[(2)x(39.09)/(0.855x6.02x10^23)]=1.5189x10^-22 cm^3

but as the cell volume is

a^3 =v

$a=\sqrt[3]{v}=\sqrt[3]{1.5189x10^{-22} } = 5.3355x10^-8$ cm

for a BCC structure, the atomic radius is equal to

$r=\frac{ax\sqrt{3} }{4}=\frac{5.3355x10^{-8}x\sqrt{3} }{4}=2.3103x10^{-8}cm$

7 0

3 years ago

How many moles are in 36 g of Beryllium (Be)?

Katarina [22]

Answer is B 4 moles .

6 0

3 years ago