Answer:
Molarity of the sodium hydroxide solution is 0.04687 M.
Explanation:
Amount of potassium hydrogen phthalate = 0.3420 g
Moles of potassium hydrogen phthalate =

According to reaction, 1 mole of potassium hydrogen phthalate reacts with 1 mole of sodium hydroxide, then 0.001675 moles pf potassium hydrogen phthalate will :
of NaOH
Moles of sodium hydroxide = 0.001675 mol
Volume of sodium hydroxide solution = 35.73 mL = 0.03573 L (1 mL = 0.001 L)
Molarity of the sodium hydroxide solution :

<h2>Answer:</h2><h3>Part 1. </h3>
Option B is correct option.
The half-reaction 2MnO2 + H2O + 2e- Mn2O3 is missing OH- ions.
Explanation:
Full equation:
2MnO2 + H2O + 2e- → Mn2O3 + 2OH-
<h3>Part 2:</h3>
The option B which is Mg is stronger reducing agent than Ag is correct option.
Explanation:
Equation:
Mg(s) + 2Ag+ (aq) → Mg2+ (aq) + 2Ag(s)
According to equation Mg converts to Mg+2 which means it gives to electron to reduce Ag. So it act as an reducing agent.
<h3>Part 3:</h3>
The correct option is B. Which is 5, 1, 8, 5, 1, 4.
Explanation:
Full equation :
5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) --> 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O (l)
<h3 />
It's an example of a molecule
Answer:
the color of the litmus paper will turn into blue color because sodium carbonate is basic in nature