Answer:
please mention the question
Answer:
The part that is put in the same time as ruthenium, but has a greater number of atoms than silver.
The empirical formula of the compound is C4H1.
An empirical formula represents the whole number ratio of various atoms present in a compound.
If the mass percent of various elements present in a compound is known, its empirical formula can be determined
We are given that a compound contains 4 mole C and 1 mole H.
Hence, the ratio of C: H is 4:1, which is already in the form of the simplest whole number.
Therefore, the empirical formula of the given compound is C4H1 and its molecular mass is 12 x 4 + 1 = 49.
To know more about "Empirical Formula", refer to the following link:
brainly.com/question/14044066?referrer=searchResults\
#SPJ4
Traditionally they include boron from group 3A, silicon and germanium in group 4A, aresnic and antimony in group 5A and tellurium from group 6A, although sometimes selenium, astatine, polonium and even bismuth have also been considered as metalloids. Typically metalloids are brittle and show a semi-metallic luster.
The six commonly recognised metalloids are boron, silicon, germanium, arsenic, antimony, and tellurium. Five elements are less frequently so classified: carbon, aluminium, selenium, polonium, and astatine.
Explanation:
i think its B but i'm not fully sure (Correct)