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3 years ago

The word supersonic describes:

Physics

2 answers:

Strike441 [17]3 years ago

5 0

The answer to your question is A.

Goryan [66]3 years ago

5 0

I think the answer is N

You might be interested in

What is the power of a student that has done a work of 10 joules in 10 seconds

Alla [95]

Answer:

1 Watt

Explanation:

P=W/t

P=10/10

P=1 Watt

8 0

3 years ago

A skydiver of 75 kg mass has a terminal velocity of 60 m/s. At what speed is the resistive force on the skydiver half that when

ankoles [38]

Answer:

The speed of the resistive force is 42.426 m/s

Explanation:

Given;

mass of skydiver, m = 75 kg

terminal velocity, $V_T = 60 \ m/s$

The resistive force on the skydiver is known as drag force.

Drag force is directly proportional to square of terminal velocity.

$F_D = kV_T^2$

Where;

k is a constant

$k = \frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2}$

When the new drag force is half of the original drag force;

$F_D_2 = \frac{F_D_1}{2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_2}{V_{T2}^2} \\\\\frac{F_D_1}{V_{T1}^2} = \frac{F_D_1}{2V_{T2}^2} \\\\\frac{1}{V_{T1}^2} = \frac{1}{2V_{T2}^2}\\\\2V_{T2}^2 = V_{T1}^2\\\\V_{T2}^2= \frac{V_{T1}^2}{2} \\\\V_{T2}= \sqrt{\frac{V_{T1}^2}{2} } \\\\V_{T2}= \frac{V_{T1}}{\sqrt{2} } \\\\V_{T2}= 0.7071(V_{T1})\\\\V_{T2}= 0.7071(60 \ m/s)\\\\V_{T2}= 42.426 \ m/s$

Therefore, the speed of the resistive force is 42.426 m/s

8 0

3 years ago

• How does AC work?

Juli2301 [7.4K]

AC reverses the current in periods, and the current flows in 2 directions.
DC only flows in one direction and is constant.

AC is typically used to transfer power over long distances from a generator to your home, stepping it up after it's generated to send it over the distance, then stepping it back down so that it is usable in your home.

DC is used typically inside of devices, as it sends a certain amount of electricity through the wires.

Nicolas Tesla, was ripped off by Edison to replace his DC stations with AC instead. ^^

4 0

3 years ago

A small 1.0 kg steel ball rolls west at 3.0 m/s collides with a large 3.0 kg ball at rest. After the collision, the small ball m

77julia77 [94]

Answer:

The direction of the momentum of the large ball after the collision with respect to east is 146.58°.

Explanation:

Given that,

Mass of large ball = 3.0 kg

Mass of steel ball = 1.0 kg

Velocity = 3.0 kg

After collision,

Velocity = 2.0 m/s

Using conservation of momentum

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}$

$3.0\times0+1.0\times(3.0)(-i)=1.0\times2(-j)+3.0\times v_{2}$

$-3i+2j=3.0\times v_{2}$

$v_{2}=-i+0.66j$

The direction of the momentum

$tan\theta=\dfrac{0.66}{-1}$

$\theta=tan^{-1}\dfrac{0.66}{-1}$

$\theta=-33.42^{\circ}$

The direction of the momentum with respect to east

$\theta=180-33.42=146.58^{\circ}$

Hence, The direction of the momentum of the large ball after the collision with respect to east is 146.58°.

7 0

3 years ago

Which student correctly identifies a similarity and a difference between vector quantities and scalar quantities?

jekas [21]

As per the question there are two physical quantities i.e scalar quantity and vector quantity.

A scalar is a physical quantity which requires only magnitude.It does not require any direction for it's complete specification.For instance we may take distance travelled,speed etc.

Unlike a scalar quantity,a vector quantity requires both magnitude as well as direction for it's complete specifications.For instance we may take displacement which is the shortest distance between two points,the velocity which is the speed in a given direction.

Hence a vector and scalar is differentiated by direction.

As per the question,the correct option will be the third option i.e C.

Carlita is right.As per her, both vector and scalar have magnitude,but only vectors have direction which is also true.

8 0

3 years ago

Read 2 more answers