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3 years ago

How is the mass and speed of a particle related to its kinetic energy?

2 answers:

5 0

The higher mass of a particle means it’ll be harder to move, slowing it down and the faster the particle is moving the higher the kinetic energy because there is more movement and pressure within the object with the energy

Furkat [3]3 years ago

4 0

The formula for KE:

1/2 x mass x (speed)^2 = KE

The formula should help you be able to dissect.

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What is the velocity of a wave with a frequency of 45 Hertz and a wavelength of 3 meters?

Juli2301 [7.4K]

Explanation:

By using v=( f )x( lambda )

v= 45 s^-1 x 3 m

Therefore v = 135 ms^-1

8 0

2 years ago

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sergij07 [2.7K]

Image #3 good luck!!!!!!!!!!!

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2 years ago

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sasho [114]

Answer:

Explanation:

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2 years ago

An AC generator has 80 rectangular loops on its armature. Each loop is 12 cm long and 8 cm wide. The armature rotates at 1200 rp

Sauron [17]

Answer: 28.96 V

Explanation:

Given

No of loops on the armature, N = 80

Length of the loop, l = 12 cm = 0.12 m

Width of the loop, b = 8 cm = 0.08 m

Speed of the armature, 1200 rpm

Magnetic field of the loop, B = 0.30 T

To solve this, we use the formula

V(max) = NBAω

Where,

A = area of loop

A = l*b = 0.12 * 0.08

A = 0.0096 m²

ω = 1200 rpm = 1200 * 2π/60 rad/s

ω = (1200 * 2 * 3.142) / 60

ω = 7540.8 / 60

ω = 125.68 rad/s

Substituting the values into the formula

V(max) = NBAω

V(max) = 80 * 0.30 * 0.0096 * 125.68

V(max) = 80 * 0.362

V(max) = 28.96 V

Therefore, the maximum output voltage of the generator would be 28.96 V

5 0

2 years ago

An oxygen molecule is adsorbed onto a small patch of the surface of a catalyst. It's known that the molecule is adsorbed on of p

FromTheMoon [43]

The given question is incomplete. The complete question is as follows.

An oxygen molecule is adsorbed onto a small patch of the surface of a catalyst. It's known that the molecule is adsorbed on 1 of 36 possible sites for adsorption. Calculate the entropy of this system.

Explanation:

It is known that Boltzmann formula of entropy is as follows.

s = k ln W

where, k = Boltzmann constant

W = number of energetically equivalent possible microstates or configuration of the system

In the given case, W = 36. Now, we will put the given values into the above formula as follows.

s = k ln W

= $1.38 \times 10^{-23} ln (36)$

= $4.945 \times 10^{-23} J/K$

Thus, we can conclude that the entropy of this system is $4.945 \times 10^{-23} J/K$ .

4 0

3 years ago