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stellarik [79]
2 years ago
8

A block with a mass of 3.7 kg slides with a speed of 2.2 m/s on a frictionless surface. The block runs into a stationary spring

with an energy of 980 J and compresses it a certain distance before it comes to rest. If the spring has a spring constant of 3200 N/m, what distance was the spring compressed by the block?
Physics
1 answer:
olga2289 [7]2 years ago
4 0
7.5 meters

Don’t need to use 980j if you use the correct equations
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Explain how a step-down transformer makes electricity safe for use in homes.
Savatey [412]

Answer:

it lowers the voltage in homes

Explanation:

this is due to safety reasons as a human cant survive power line voltages which are between 150k and 760k and if you plugged anything short of a piece of 1 inch thick wire not counting insulation it would immediately start smoking and burn the cable.

3 0
3 years ago
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Can someone help me with this question
Mademuasel [1]

Answer:

Net force: 20 N to the right

mass of the bag: 20.489 kg

acceleration:  0.976  m/s^2

Explanation:

Since the normal force and the weight are equal in magnitude but opposite in direction, they add up to zero in the vertical direction. In the horizontal direction, the 195 N tension to the right minus the 175 force of friction to the left render a net force towards the right of magnitude:

195 N - 175 N = 20 N

So net force on the bag is 20 N to the right.

The mass of the bag can be found using the value of the weight force: 201 N:

mass = Weight/g = 201 / 9.81 = 20.489 kg

and the acceleration of the bag can be found as the net force divided by the mass we just found:

acceleration = 20 N / 20.489 kg = 0.976  m/s^2

8 0
3 years ago
By newton third law of motion, we know that if a rocket ship pushes down on the ground, the ground will push back up on the rock
Furkat [3]

We don't know that at all. The 3rd law says that the REaction is opposite and EQUAL to the action.  We don't know where that "twice as much" comes from.

6 0
3 years ago
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A convex mirror has a focal length of 15cm. If the object is 35cm from the mirror and is 2cm tall, what is the magnification? Ro
Verizon [17]

Answer:

The magnification is 0.3

Explanation:

Given:

The focal length of the convex mirror, f = 15 cm

for convex mirror f = -f = -15 cm

The distance of object, u = 35 cm

Height of the object, h = 2 cm

Now, using the mirror formula, we have

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

where, v is the distance of the image

on substituting the values, we get

\frac{1}{-15}=\frac{1}{35}+\frac{1}{v}

or

-\frac{1}{v}=\frac{1}{35}-\frac{1}{-15}

or

v = -10.5 cm

now, the magnification (m) is given as:

m = -\frac{v}{u}

on substituting the values, we get

m = -\frac{-10.5}{35}

or

m = 0.3

Hence, the magnification is 0.3

6 0
3 years ago
Tungsten has a temperature coefficient of resistivity of 0.0045 (c°)-1. a tungsten wire is connected to a source of constant vol
Murljashka [212]

Answer:

131.1^{\circ}C

Explanation:

The power delivered in the wire is given by:

P=\frac{V^2}{R}

where V is the voltage of the battery and R is the resistance of the wire.

Since the voltage of the battery is constant, we can rewrite this equation as follows:

V^2 = PR=const. (1)

At the beginning, the initial resistance is R_0, and the power delivered is P_0. Later, when the temperature increases, the power becomes P_1 = \frac{2}{3}P_0, and the new resistance is R_1. Using (1), we can write

P_0 R_0 = \frac{2}{3}P_0 R_1\\R_1 = \frac{3}{2}\frac{P_0 R_0}{P_0}=\frac{3}{2}R_0 (2)

So, the new resistance must be 3/2 of the initial resistance.

We know that the resistance increases linearly with the temperature, as

R_1 = R_0 (1+\alpha \Delta T)

where

\alpha = 0.0045 ^{\circ}C^{-1} is the temperature coefficient

\Delta T is the change in temperature

Using (2), we can rewrite this equation as

\frac{3}{2}R_0 = R_0(1+ \alpha \Delta T)

and we find:

\frac{3}{2}=1+\alpha \Delta T\\\Delta T=\frac{\frac{3}{2}-1}{\alpha}=111.1 ^{\circ}

So, the new temperature of the wire must be

T_f = 21^{\circ}+111.1^{\circ}=132.1^{\circ}

6 0
3 years ago
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