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Arisa [49]
3 years ago
7

As a bond is broken in a compound the potential energy of the atoms generally does what

Chemistry
1 answer:
hichkok12 [17]3 years ago
6 0
When a bond is broken that should be a type of reaction. When bonds are broken sometimes heat is released.
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What is the percent composition of chlorine in the compound Ba(ClO3)2?
tia_tia [17]

You're going to divide the mass of chlorine within the compound by the mass of the compound, and then multiply the result by 100 to get the answer

6 0
2 years ago
How many moles of H2O are in 64.0 g of H2O
Alina [70]

Answer:

Explanation:

stoichiometry of C₂H₂ to H₂O is 2:2.

Number of moles of C₂H₂ = molar mass of C₂H₂  

Since the molar mass of C₂H₂  is 26 g/mol.

Number of C₂H₂  moles reacted = 64.0 g / 26 g/mol = 2.46 mol.

according to a molar ratio of 2:2.

the number of H₂O moles formed = a number of C₂H₂  moles reacted.

Therefore the number of H₂O moles produced = 2.46 mol

8 0
1 year ago
A certain compound was found to have the molecular formula C5H12O2. To which of the following compound classes could the compoun
IgorC [24]

Answer : The given compound belongs to ether and alcohol.

Explanation :

The chemical formula of the given compound is, C_5H_{12}O_2

First we have to calculate the degree of unsaturation.

Formula used:

Degree of unsaturation = \frac{2C+2+N-X-H}{2}

where,

C = number of carbon

H = number of hydrogen

N = number of nitrogen

X = number of halogen

Degree of unsaturation = \frac{2\times 5+2+0-0-12}{2}=0

The degree of unsaturation is, 0 that means there is no double or triple bond in the compound only single bond is present between the atoms.

Thus, the given compound belongs to ether and alcohol.

6 0
3 years ago
What are examples of inferred energy?
Kisachek [45]
Using a stove to heat up water.  
6 0
3 years ago
Read 2 more answers
A solution prepared by mixing 10 ml of 1 m hcl and 10 ml of 1.2 m naoh has a ph of
blagie [28]

Answer: pH of resulting solution will be 13

Explanation:

pH is the measure of acidity or alkalinity of a solution.

Moles of H^+ ion = Molarity\times {\text {Volume in L}}=1M\times 0.01L=0.01mol

Moles of OH^- ion = Molarity\times {\text {Volume in L}}=1.2M\times 0.01L=0.012mol

HCl+NaOH\rightarrow NaCl+H_2O

For neutralization:

1 mole of H^+ ion will react with 1 mole of OH^- ion

0.01 mol of H^+  ion will react with =\frac{1}{1}\times 0.01mole of OH^- ion

Thus (0.012-0.01)= 0.002 moles of OH^- are left in 20 ml or 0.02 L of solution.

[OH^-]=\frac{0.002}{0.02L}=0.1M

pOH=-log[OH^-]

pOH=-log[0.1]=1

pH+pOH=14

pH=14-1=13

Thus the pH of resulting solution will be 13

7 0
2 years ago
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