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3 years ago

As a bond is broken in a compound the potential energy of the atoms generally does what

Chemistry

1 answer:

hichkok12 [17]3 years ago

6 0

When a bond is broken that should be a type of reaction. When bonds are broken sometimes heat is released.

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What is the percent composition of chlorine in the compound Ba(ClO3)2?

tia_tia [17]

You're going to divide the mass of chlorine within the compound by the mass of the compound, and then multiply the result by 100 to get the answer

6 0

2 years ago

How many moles of H2O are in 64.0 g of H2O

Alina [70]

Answer:

Explanation:

stoichiometry of C₂H₂ to H₂O is 2:2.

Number of moles of C₂H₂ = molar mass of C₂H₂

Since the molar mass of C₂H₂ is 26 g/mol.

Number of C₂H₂ moles reacted = 64.0 g / 26 g/mol = 2.46 mol.

according to a molar ratio of 2:2.

the number of H₂O moles formed = a number of C₂H₂ moles reacted.

Therefore the number of H₂O moles produced = 2.46 mol

8 0

1 year ago

A certain compound was found to have the molecular formula C5H12O2. To which of the following compound classes could the compoun

IgorC [24]

Answer : The given compound belongs to ether and alcohol.

Explanation :

The chemical formula of the given compound is, $C_5H_{12}O_2$

First we have to calculate the degree of unsaturation.

Formula used:

Degree of unsaturation = $\frac{2C+2+N-X-H}{2}$

where,

C = number of carbon

H = number of hydrogen

N = number of nitrogen

X = number of halogen

Degree of unsaturation = $\frac{2\times 5+2+0-0-12}{2}=0$

The degree of unsaturation is, 0 that means there is no double or triple bond in the compound only single bond is present between the atoms.

Thus, the given compound belongs to ether and alcohol.

6 0

3 years ago

What are examples of inferred energy?

Kisachek [45]

Using a stove to heat up water.

6 0

3 years ago

Read 2 more answers

A solution prepared by mixing 10 ml of 1 m hcl and 10 ml of 1.2 m naoh has a ph of

blagie [28]

Answer: pH of resulting solution will be 13

Explanation:

pH is the measure of acidity or alkalinity of a solution.

Moles of $H^+$ ion = $Molarity\times {\text {Volume in L}}=1M\times 0.01L=0.01mol$

Moles of $OH^-$ ion = $Molarity\times {\text {Volume in L}}=1.2M\times 0.01L=0.012mol$

$HCl+NaOH\rightarrow NaCl+H_2O$

For neutralization:

1 mole of $H^+$ ion will react with 1 mole of $OH^-$ ion

0.01 mol of $H^+$ ion will react with = $\frac{1}{1}\times 0.01mole$ of $OH^-$ ion

Thus (0.012-0.01)= 0.002 moles of $OH^-$ are left in 20 ml or 0.02 L of solution.

$[OH^-]=\frac{0.002}{0.02L}=0.1M$

$pOH=-log[OH^-]$

$pOH=-log[0.1]=1$

$pH+pOH=14$

$pH=14-1=13$

Thus the pH of resulting solution will be 13

7 0

2 years ago