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ehidna [41]
3 years ago
6

How many moles of H2 would be required to produce 5.0 moles of water

Chemistry
1 answer:
earnstyle [38]3 years ago
3 0
5 moles of H2
..............
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A 2.950×10−2 M solution of glycerol (C3H8O3) in water is at 20.0∘C. The sample was created by dissolving a sample of C3H8O3 in w
11111nata11111 [884]

Answer:

The molality of the glycerol solution is 2.960×10^-2 mol/kg

Explanation:

Number of moles of glycerol = Molarity × volume of solution = 2.950×10^-2 M × 1 L = 2.950×10^-2 moles

Mass of water = density × volume = 0.9982 g/mL × 998.7 mL = 996.90 g = 996.90/1000 = 0.9969 kg

Molality = number of moles of glycerol/mass of water in kg = 2.950×10^-2/0.9969 = 2.960×10^-2 mol/kg

7 0
3 years ago
The half life of 226/88 Ra is 1620 years. How much of a 12 g sample of 226/88 Ra will be left after 8 half lives?
Aloiza [94]

Answer:

0.0468 g.

Explanation:

  • The decay of radioactive elements obeys first-order kinetics.
  • For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).

Where, k is the rate constant of the reaction.

t1/2 is the half-life time of the reaction (t1/2 = 1620 years).

∴ k = ln2/(t1/2) = 0.693/(1620 years) = 4.28 x 10⁻⁴ year⁻¹.

  • For first-order reaction: <em>kt = lna/(a-x).</em>

where, k is the rate constant of the reaction (k = 4.28 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = t1/2 x 8 = 1620 years x 8 = 12960 year).

a is the initial concentration (a = 12.0 g).

(a-x) is the remaining concentration.

∴ kt = lna/(a-x)

(4.28 x 10⁻⁴ year⁻¹)(12960 year) = ln(12)/(a-x).

5.54688 = ln(12)/(a-x).

Taking e for the both sides:

256.34 = (12)/(a-x).

<em>∴ (a-x) = 12/256.34 = 0.0468 g.</em>

8 0
3 years ago
Why do substances with weak intermolecular forces form solids at low melting points?
Advocard [28]
To make any substance solid, molecules must come very close to each other. Substances with weak intermolecular forces have weak bonding. Hence to make their molecules come close to each other, we must provide low temperature. 
7 0
3 years ago
19. What is sthe mass of 6.02 x 1024 atoms
alekssr [168]

The mass of magnesium in 6.02 \times 10^{24} atoms is 240 g.

Answer: Option A

<u>Explanation:</u>

First, we have to convert the atoms to moles of magnesium.

We know that 6.02 \times 10^{24} atoms are present in 1 mole of magnesium. So,

    \text { 1 atom }=\frac{1}{6.02 \times 10^{24}} \text { moles }

    6.02 \times 10^{24} \text { atoms }=\frac{6.02 \times 10^{24}}{6.02 \times 10^{23}} \text { moles }=10 \text { moles }

Thus,

     Mass of M g= molar mass of M g \times No. of moles of M g

     \text { Mass of } M g=24 \times 10=240 g

Thus, 240 g of Magnesium is present in 6.02 \times 10^{24} atoms.

4 0
3 years ago
Explain how synthesis and decomposition reactions can be reverse of one another
lana66690 [7]

Decompostion reaction have the general chemical reaction of: AB = A + B while synthesis reactions are of the general equation A + B = AB. These reaction can be the reverse of each other because ones building a compound (synthesis) and ones breaking down a compound (decomposition). For example, when reacting carbon and oxygen for a synthesis reaction we have: C + O2 = CO2 and for a decomposition reaction we have: CO2 = C + O2. Thus, these two reactions are the reverse of each other.

5 0
3 years ago
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