Tilited walls and fences are a sign (mudflow or creep?) is occuring

For a reversible reaction, what would a large equilibrium constant indicate?

siniylev [52]

(D) At equilibrium, the concentration of the products will be much higher than the concentration of the reactants.

8 0

3 years ago

(6) A mixture of 40.0 g of oxygen and 40.0 g of helium has a total pressure of 0.900 atm.

Elena L [17]

Answer:

Partial pressure of oxygen $= 0.100$ atm

Partial pressure of Helium $= 0.800$ atm

Explanation:

We will first find the number of moles of each gas

The molar mass of oxygen is $32$ grams per mole

The molar mass of helium is $4$ grams per mole

The number of moles of oxygen in the solution

$\frac{40}{32} \\1.25$

The number of moles of helium in the solution

The number of moles of oxygen in the solution

$\frac{40}{4}\\10$

Total number of moles in the solution is equal to

$10 + 1.25 \\11.25$

Partial pressure of oxygen

$\frac{1.25 }{11.25} * 0.900$ atm

$= 0.100$ atm

Partial pressure of Helium

$\frac{10 }{11.25} * 0.900$ atm

$= 0.800$ atm

5 0

3 years ago

What is the mass of 0.7891 mol of (fe2o3)?

Serjik [45]

Molar mass F₂O₃ = 159.69 g/mol

1 mole ------------------ 159.69 g
0.7891 moles ---------- ? g

mass = 0.7891 x 159.69 / 1

= 126.01 g

hope this helps!

4 0

3 years ago

You are conducting a plant growth experiment and need to generate a solution with growth factor, auxin or indole-3-acetic acid.

Yuki888 [10]

Answer:

7,01 g of indole-3-acetic acid

Explanation:

The milimolar concentration (mM) is defined as the ratio of milimoles per Liter of solution. 400mM means 400mmoles / L that is the same of 0,4mol / L

100mL are 0,1L. Using these values:

0,1L × (0,4mol / L ) = 0,04moles of indole-3-acetic acid.

As the MW of the molecule is 175,2 g/mol:

0,04mol × (175,2g / mol) = 7,01 g of indole-3-acetic acid

Thus, you need 7,01 g of indole-3-acetic acid to generate your solution.

I hope it helps!

5 0

3 years ago

Baking soda (sodium bicarbonate) is often used to neutralize spills of acids on the benchtop of the laboratory. What mass of sod

FrozenT [24]

Answer : The mass of $NaHCO_3$ needed is, 12.7 grams.

Explanation :

First we have to calculate the moles of HCl.

$\text{Moles of }HCl=\text{Concentration of }HCl\times \text{Volume of }HCl$

$\text{Moles of }HCl=6.01M\times 0.0252L=0.151mol$

Now we have to calculate the moles of $NaHCO_3$

The balanced neutralization reaction will be:

$HCl+NaHCO_3\rightarrow NaCl+H_2O+CO_2$

From the balanced chemical reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of $NaHCO_3$

So, 0.151 mole of HCl neutralizes by 0.151 mole of $NaHCO_3$

Now we have to calculate the mass of $NaHCO_3$

$\text{ Mass of }NaHCO_3=\text{ Moles of }NaHCO_3\times \text{ Molar mass of }NaHCO_3$

Molar mass of $NaHCO_3$ = 84 g/mole

$\text{ Mass of }NaHCO_3=(0.151moles)\times (84g/mole)=12.7g$

Therefore, the mass of $NaHCO_3$ needed is, 12.7 grams.

7 0

3 years ago

Tilited walls and fences are a sign (mudflow or creep?) is occuring​

Tilited walls and fences are a sign (mudflow or creep?) is occuring