Changes to Earth's Surface

HELP HELP HELP HELP Please Help Will Mark Brainlyliest How does the amount and type of fuel impact the distance a spacecraft can

ohaa [14]

Answer:

Explanation:

Defining Emotional Appeal

An emotional appeal is used to sway the emotions of an audience to make them support the speaker’s argument.

LEARNING OBJECTIVES

Break down the components that make up an emotional appeal

KEY TAKEAWAYS

Key Points

Pathos represents an appeal to the emotions of an audience.

An emotional appeal uses the manipulation of the emotions rather than valid logic to win an argument.

Emotional appeal is a logical fallacy, whereby a debater attempts to win an argument by trying to get an emotional reaction from the opponent and audience.

In debating terms, emotional appeals are often effective as a rhetorical device, but are generally considered naive or dishonest as a logical argument, since they often appeal to the prejudices of listeners rather than offer a sober assessment of a situation.

Key Terms

logical fallacy: A fallacy; a clearly defined error in reasoning used to support or refute an argument, excluding simple unintended mistakes.

Emotional Appeal Defined

Pathos represents an appeal to the audience’s emotions. Pathos is a communication technique used most often in rhetoric (where it is considered one of the three modes of persuasion, alongside ethos and logos), and in literature, film, and other narrative art.

Emotional appeal can be accomplished in a multitude of ways:

By a metaphor or storytelling, common as a hook

By a general passion in the delivery

By an overall emotion

By the sympathies of the speech or writing as determined by the audience

The pathos of a speech or writing is only ultimately determined by the audience.

The Purpose of an Emotional Appeal

An emotional appeal is directed to sway an audience member’s emotions and uses the manipulation of the recipient’s emotions rather than valid logic to win an argument. An emotional appeal uses emotions as the basis of an argument’s position without factual evidence that logically supports the major ideas endorsed by the presenter. In an emotional appeal, persuasive language is used to develop the foundation of an appeal to emotion-based arguments instead of facts. Therefore, the validity of the premises that establish such an argument does not prove to be verifiable.

A US soldier holds his daughter and his son.

Emotional Appeal: A picture like this could be used as an emotional appeal for a charity campaign to increase funding for soldiers’ families.

Emotional appeal is a logical fallacy, whereby a debater attempts to win an argument by trying to get an emotional reaction from the opponent and audience. It is generally characterized by the use of loaded language and concepts (God, country, and apple pie being good concepts; drugs and crime being bad ones). In debating terms, emotional appeals are often effective as a rhetorical device, but are generally considered naive or dishonest as a logical argument, since they often appeal to the prejudices of listeners

3 0

3 years ago

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At 14,000 ft elevation the air pressure drops to 0.59 atm. Assume you take a 1L sample of air at this altitude and compare it to

Ray Of Light [21]

Answer:

There are 0.1125 g of O₂ less in 1 L of air at 14,000 ft than in 1 L of air at sea level.

Explanation:

To solve this problem we use the ideal gas law:

PV=nRT

Where P is pressure (in atm), V is volume (in L), n is the number of moles, T is temperature (in K), and R is a constant (0.082 atm·L·mol⁻¹·K⁻¹)

Now we calculate the number of moles of air in 1 L at sea level (this means with P=1atm):

1 atm * 1 L = n₁ * 0.082 atm·L·mol⁻¹·K⁻¹ * 298 K

n₁=0.04092 moles

Now we calculate n₂, the number of moles of air in L at an 14,000 ft elevation, this means with P = 0.59 atm:

0.59 atm * 1 L = n₂ * 0.082 atm·L·mol⁻¹·K⁻¹ * 298 K

n₂=0.02414 moles

In order to calculate the difference in O₂, we substract n₂ from n₁:

0.04092 mol - 0.02414 mol = 0.01678 mol

Keep in mind that these 0.01678 moles are of air, which means that we have to look up in literature the content of O₂ in air (20.95%), and then use the molecular weight to calculate the grams of O₂ in 20.95% of 0.01678 moles:

$0.01678mol*\frac{20.95}{100} *32\frac{g}{mol} =0.1125 gO_{2}$

4 0

4 years ago

8. What is the electron configuration of the element with 27 protons?

Komok [63]

Explanation:

Number of protons means atomic number of an atom. Element whose atomic number is 27 is cobalt.

When an atom is neutral then the number of protons equal the number of electrons.

Cobalt is a transition element or it is also known as d-block element. The electronic configuration of cobalt is as follows.

$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{7}$

4 0

3 years ago

When 943 J of heat is added to 10 grams of oil at 28˚C , the temperature increases to 89˚C. What is the specific heat of the oil

IgorLugansk [536]

Answer: 1.55 Jg°C

Explanation:

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = 943 joules

Mass of oil = 10g

C = ? (let unknown value be Z)

Φ = (Final temperature - Initial temperature)

= 89°C - 28°C = 61°C

Then, Q = MCΦ

943 J = 10g x Z x 61°C

943J = 610g°C x Z

Z = (943J / 610g°C)

Z = 1.55 Jg°C

Thus, the specific heat of the oil is 1.55 Jg°C

7 0

4 years ago

In standardizing the solution of aqueous sodium hydroxide, a chemist overshoots the end point and adds too much naoh(aq). would

irinina [24]

Answer: Concentration of NaOH calculated will be underestimated.

Explanation:

End point is an observational point , which tells us about the completion of reaction between the titrant (solution in burette) and titre(solution in conical flask) in titration experiment.

In this case , NaOH is titrant whose concentration is unknown.

$M_1=\text{molarity of titre}$ , $M_2=\text{molarity of NaOH}$

$V_1=\text{volume of titre}$ , $V_2=\text{volume of NaOH}$

$M_1V_1=M_2V_2$

$M_2=\frac{M_1V_1}{V_2}$ ....(1)

According to question a chemist overshoots the end point and adds to much of NaOH solution, which means increase in the value of $V_2$ .

Then the value of $M_2$ in equation (1), will get lowered , which means that the concentration of NaOH was lower than that of the actual value. Hence underestimated concentration of NaOH.

8 0

3 years ago