Answer:
The capillary rise of the glycerin is most nearly 
Explanation:
From the question we are told that
The diameter of the glass tube is 
The density of glycerin is 
The surface tension of the glycerin is 
The capillary rise of the glycerin is mathematically represented as

substituting value


Therefore the height of the glass tube the glycerin was able to cover is
Answer:
2.083 V.
Explanation:
Stopping potential is the potential that is required to stop the current to zero . This potential is applied externally to oppose the potential created by the photoelectric effect . It gives the measure the photoelectric potential being generated .
Here current drops to 25 μA to 19 μA by a potential of 500mV
Change in current
= 25 - 19 = 6 μA
Voltage requirement for unit reduction in current
= 500 / 6 μA
To reduce current 0f 25 μA
requirement of V = (500 / 6 ) x 25 = 2083.33 mV = 2.083 V.
<h3><u>Answer</u>;</h3>
-The total momentum of an isolated system is constant.
-The total momentum of any number of particles is equal to the vector sum of the momenta of the individual particles.
-The vector sum of forces acting on a particle equals the rate of change of momentum of the particle with respect to time.
<h3><u>Explanation</u>;</h3>
- Momentum is a vector quantity, and therefore we need to use vector addition when summing together the momenta of the multiple bodies which make up a system.
- The vector sum of forces acting on a particle is equivalent to the rate of change of momentum of the particle with respect to time. This is according to the Newton's second Law of motion. In mathematical terms, ֿF = d ֿp/dt, that is F= ma.
- According to the Law of conservation of Momentum, or a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
Answer:
(a) 0.345 T
(b) 0.389 T
Solution:
As per the question:
Hall emf, 
Magnetic Field, B = 0.10 T
Hall emf, 
Now,
Drift velocity, 

Now, the expression for the electric field is given by:
(1)
And

Thus eqn (1) becomes
where
d = distance
(2)
(a) When 

(b) When 
