All categories

3 years ago

If a behavior tends to increase after a consequence occurs, that consequence is most likely used as.

1 answer:

4 0

<span>If a behavior tends to increase after a consequence occurs, that consequence is most likely used as a catalyst. In terms of chemical reactions, catalysts are used to increase the rate of reaction. Given that, when an object causes a situation to become more frequent, then it is considered as a catalyst.</span>

You might be interested in

Two billiard balls (each with mass equal to 170 g) collide head-on along the same line. Billiard ball A originally traveled east

barxatty [35]

Answer:

lucky mauld mauldgomary was an british poet...

5 0

3 years ago

a bungee jumper momentarily comes to rest at the bottom of the dive before he springs back upward. at that moment, is the bungee

barxatty [35]

Answer:

Explanation:

No, the bungee jumper is not at equilibrium.

This can be explained when we consider a bungee jumper as a mass that is undergoing simple harmonic motion. At extreme points i.e. at the bottom, the velocity of the jumper is zero but not the acceleration because it is acting in the opposite direction that is why the jumper moves upward.

3 0

3 years ago

Read 2 more answers

Reading glasses of what power are needed for a person whose near point is 125 cm , so that he can read a computer screen at 54 c

Burka [1]

Answer:

1.11 dioptre

Explanation:

$d_{i}$ = Distance of the image = - (125 - 2) = - 123 cm

$d_{o}$ = Distance of the object = 54 - 2 = 52 cm

$f$ = Focal length of the lens

Using the equation

$\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}$

$\frac{1}{52} + \frac{- 1}{123} = \frac{1}{f}$

$f = 90.1$ cm

Power of the lens is given as

$P = \frac{100}{f}$

$P = \frac{100}{90.1}$

$P = 1.11$ Dioptre

3 0

3 years ago

Sprinting near the end of a race, a runner with a mass 63 kg accelerates from a speed of 25 m/s to a speed of 26 m/s in 54 s. To

gavmur [86]

Answer:

1.1655 N

Explanation:

Given that,

Initial speed, u = 25 m/s

Final speed, v = 26 m/s

Time taken, t = 54 s

So, Applying equation of motion as:

$v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{26-25}{54}\ m/s^2\\\Rightarrow a=0.0185\ m/s^2$

According to the Newton's second law of motion:-

$Force=Mass\times Acceleration$

Mass = 63 kg

So,

$Force=63\times 0.0185\ kgm/s^2$

<u>Force = 1.1655 N</u>

5 0

4 years ago

Earth quakes near the California Bay typically occur at frequencies of 1.5HZ or 2.8HZ. If you were engineering a new building in

jekas [21]

Answer:

2.0 Hz

Explanation:

2.0 Hz is the most closest to the middle number in between 2.8 and 1.5 Hz. 1.6 Hz would not be suitable as it is too close to 1.5 Hz and 2.7 would also not be suitable as it is too close to 2.8 Hz.

8 0

2 years ago