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3 years ago

11. Which one of the following contains the same number of atoms as 7 g

Chemistry

1 answer:

Vesna [10]3 years ago

5 0

C) 4g of sulphur is the answer

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Write an equilibrium equation that shows bisulfate acting as a weak acid in water.

NemiM [27]

Answer:

Explanation:

Bisulphate ion is a weak acid as it can form hydronium ion in water .

HSO₄⁻ + H₂O ⇄ SO₄⁻² + H₃O⁺

The equilibrium constant of this reaction is very small , hence bisulphate ion is very weak acid.

4 0

3 years ago

Does water burn? for my sister that says water does burn

DedPeter [7]

No, water can’t burn

5 0

3 years ago

Read 2 more answers

8. which change in state is associated with the heat of vaporization,

rewona [7]

The answer is 2, liquid to vapor because vaporization is the process of liquids to vapors.

8 0

3 years ago

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: E = R_y/n^2 In this equation R_y stands

Katarina [22]

Answer:

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

Explanation:

Given :

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

$E=\frac{R_y}{n^2}$

$R_y=2.18\times 10^{-18} J$ = Rydberg energy

n = principal quantum number of the orbital

Energy of 11th orbit = $E_{11}$

$E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J$

Energy of 10th orbit = $E_{10}$

$E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J$

Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.

$E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J$

$=E'=0.38\times 10^{-20} J$

$\lambda =\frac{hc}{E'}$ (Planck's' equation)

$\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}$

$\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m$

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

3 0

3 years ago

If an object with a volume of 105 mL and a density of 0.801 g/mL, what is the objects mass?

garik1379 [7]

Answer:

The objects mass is 84, 105 g. See the explanation below, please.

Explanation:

We use the formula:

Density= mass/volume

Mass= Density x volume =0.801 g/mL x 105 mL = 84, 105 g

6 0

3 years ago