Answer:
Mn is the oxidizing agent.
N is the reducing agent.
Explanation:
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In this case, according to the undergoing chemical reaction, it is seen that the manganese in KMnO4 has an oxidation state of 7+, in MnSO4 of 2+ and nitrogen in KNO2 is 3+ and in KNO3 is 5+; thus we have the following half-reactions:
![Mn^{7+}+5e^-\rightarrow Mn^{2+}\\\\N^{3+}\rightarrow N^{5+}+2e^-](https://tex.z-dn.net/?f=Mn%5E%7B7%2B%7D%2B5e%5E-%5Crightarrow%20Mn%5E%7B2%2B%7D%5C%5C%5C%5CN%5E%7B3%2B%7D%5Crightarrow%20N%5E%7B5%2B%7D%2B2e%5E-)
Thus, since manganese is undergoing a decrease in the oxidation state, we infer it is the oxidizing agent whereas nitrogen, undergoing an increase in the oxidation state is the reducing agent.
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Answer:
The physical states that are represented by each graph region are the liquid and the solid, the highest temperature is the liquid and as it freezes it becomes a solid. The particles change because when it's a liquid, it isn't that compact it's just spreading smootly but as it freezes the atoms start to stick together and become compact.
Explanation:
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