1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nataly_w [17]
2 years ago
5

The image shows a molecular model of a compound using balls and sticks. Each ball is an atom and each stick is a bond. If you we

re to use balls and sticks to model a molecule of an element, how must your model differ from what’s shown?
A.

The sticks must be shorter.

B.

The balls must be the same color.

C.

The balls must be smaller.

D.

The balls must change to cubes.

Chemistry
2 answers:
Yuri [45]2 years ago
7 0

Answer: Option (B) is the correct answer.

Explanation:

An element contains atoms with same atomic number. This means that each atom of an element will have same number of protons.

For example, in oxygen element all atoms of oxygen will have atomic number 8.

Thus, we can conclude that if you were to use balls and sticks to model a molecule of an element, then the balls must be the same color.

Zielflug [23.3K]2 years ago
3 0
Hi , the answers must be part B
You might be interested in
Primary succession is most likely caused by?
disa [49]

Answer:

volcanic eruption.

mark my answer as brainlest......

3 0
3 years ago
When titrating a strong acid with a strong base, after the equivalence point is reached, the pH will be determined exclusively b
Arte-miy333 [17]

Answer:

B) hydroxide concentration

Explanation:

Hello,

In this case, since we are talking about strong both base and acid, since the base is the titrant and the acid the analyte, once the equivalence point has been reached, some additional base could be added before the experimenter realizes about it, therefore, since the titrant is a strong base, it completely dissociates in hydroxide ions and metallic ions which allows us to compute the pOH of the solution by known the hydroxide ions concentration.

After that, due to the fact that the pH is related with the pOH as shown below:

pH=14-pOH

We can directly compute the pH.

Best regards.

5 0
2 years ago
Conduct metric Titration of H_2(SO_4) and Ba(OH)_2 Write an equation (including states of matter) for the reaction between H_2(S
meriva

Answer:

a) H₂SO₄ + Ba(OH)₂ ⇄ BaSO₄(s) + 2 H₂O(l)

b) H₂SO₄, H⁺, HSO₄⁻, SO₄²⁻. H₂O, H⁺, OH⁻.

c) H⁺, HSO₄⁻, SO₄²⁻

d) As the titration takes place, reaction [1] proceeds to the right. The conductivity of the solution decreases because the amount of H⁺, HSO₄⁻, SO₄²⁻ decreases. The formed solid is barium sulfate BaSO₄. Since BaSO₄ is very insoluble, the main responsible for conductivity are still H⁺, HSO₄⁻ and SO₄²⁻,

e) At the equivalence point equivalent amounts of H₂SO₄ and Ba(OH)₂ react. The conducting species are Ba²⁺, SO₄²⁻, H⁺ and OH⁻.

f) After the equivalence point there is an excess of Ba(OH)₂. The ions Ba²⁺ and OH⁻ are responsible for the increase in the conductivity, being the major conducting species.

Explanation:

a) Write an equation (including states of matter) for the reaction between H₂SO₄ and Ba(OH)₂.

The <em>balanced equation</em> is:

H₂SO₄ + Ba(OH)₂ ⇄ BaSO₄(s) + 2 H₂O(l)   [1]

b) At the very start of the titration, before any titrant has been added to the beaker, what is present in the solution?

In the beginning there is H₂SO₄ and the ions that come from its <em>dissociation reactions</em>: H⁺, HSO₄⁻, SO₄²⁻. There is also H₂O and a very small amount of H⁺ and OH⁻ coming from its <em>ionization</em>.

H₂SO₄(aq) ⇄ H⁺(aq) + HSO₄⁻(aq)

HSO₄⁻(aq) ⇄ H⁺(aq) + SO₄²⁻(aq)

H₂O(l)  ⇄ H⁺(aq) + OH⁻(aq)

c) What is the conducting species in this initial solution?

The main responsible for conductivity are the <em>ions</em> coming from H₂SO₄: H⁺, HSO₄⁻, SO₄²⁻.

d) Describe what happens as titrant is added to the beaker. Why does the conductivity of the solution decrease? What is the identity of the solid formed? What is the conducting species present in the beaker?

As the titration takes place, reaction [1] proceeds to the right. The conductivity of the solution decreases because the amount of H⁺, HSO₄⁻, SO₄²⁻ decreases. The formed solid is barium sulfate BaSO₄. Since BaSO₄ is very insoluble, the main responsible for conductivity are still H⁺, HSO₄⁻ and SO₄²⁻,

e) What happens when the conductivity value reaches its minimum value (which is designated as the equivalence point for this type of titration)? What is the conducting species in the beaker?

At the <em>equivalence point</em> equivalent amounts of H₂SO₄ and Ba(OH)₂ react. Only BaSO₄ and H₂O are present, and since they are <em>weak electrolytes</em>, there is a small amount of ions to conduct electricity. The conducting species are Ba²⁺ and SO₄²⁻ coming from BaSO₄ and H⁺ and OH⁻ coming from H₂O.

f) Describe what happens at additional titrant is added past the equivalence point. Why does the conductivity of the solution increase? What is the conducting species present in the beaker?

After the equivalence point there is an excess of Ba(OH)₂. The ions Ba²⁺ and OH⁻ are responsible for the increase in the conductivity, being the major conducting species.

7 0
3 years ago
How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate is combined with 15.0 g of hydrochloric aci
horsena [70]

Answer:

22.7 g of CaCl₂ are produced in the reaction

Explanation:

This is the reaction:

CaCO₃ +  2HCl  →  CaCl₂  + CO₂  +  H₂O

Now, let's determine the limiting reactant.

Let's divide the mass between the molar mass, to find out moles of each reactant.

29 g / 100.08 g/m = 0.289 of carbonate

15 g / 36.45 g/m = 0.411 of acid

1 mol of carbonate must react with 2 moles of acid

0.289 moles of carbonate will react with the double of moles (0.578)

I only have 0.411 of HCl, so the acid is the limiting reactant.

Ratio is 2:1, so I will produce the half of moles, of salt.

0.411 / 2 = 0.205 moles of CaCl₂

Mol . molar mass = mass → 0.205 m . 110.98 g/m = 22.7 g

5 0
3 years ago
Which statement describes why sodium reacts more vigorously than magnesium to hydrochloric acid? Refer to the periodic table. Ci
lions [1.4K]

Sodium has a lower ionization energy than magnesium describes why sodium reacts vigorously than magnesium chloride.

<h3>Why is sodium more reactive than magnesium?</h3>
  • Sodium is more reactive than magnesium because it has the ability to easily lose electron, hence have lower ionization energy.
  • Sodium belong to group one on the periodic table and they are called akali metal while magnesium belong to group two on the periodic table and they are called alkali Earth metal.

  • Sodium and magnesium belong to the in the 3rd period. Iin the outermost energy level sodium has one electron but magnesium has 2 electrons. Therefore, there is more attraction abetween the nucleus and electrons in magnesium than that of sodium.

Therefore, sodium is more reactive than magnesium chloride because of lower ionization energy.

For more details on sodium reactivity, check the link below.

brainly.com/question/6837593

8 0
2 years ago
Read 2 more answers
Other questions:
  • What mass of a .413% KCN solution contains 545 mg of KCN?
    10·1 answer
  • In the electron transport system, hydrogen atoms removed from NADH ultimately end up as part of _____
    5·1 answer
  • Which of the following statement best describes wavelength?
    11·2 answers
  • Hey guys I need help with these questions on my test these are my questions I have not done it ***there are 4 pics I put***
    6·1 answer
  • A cup of coffee(140g) cools from 75 degrees Celsius down to comfortable room temperature 20 degrees Celsius. How much energy doe
    13·1 answer
  • How many atoms are there in 4500 grams of sulfur(s)?plaease help
    8·1 answer
  • A solution of nitric acid has a [H3O+] = 2.8 x 10-6 M. What is the pH?
    15·1 answer
  • If two oceanic plates move towards each other at a convergent boundary, then_____ may occur.
    15·2 answers
  • The reaction 2NoBr(g) ---&gt; 2NO(g)+Br2(g) is a second order reaction with a rate constant of 0.80M^-1 s^-1 at 11 C. If the ini
    13·1 answer
  • Hello people ~<br>help me with these questions ​
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!