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Aleksandr [31]
3 years ago
5

I have coronia virus say something positive to help me through

Chemistry
2 answers:
Rashid [163]3 years ago
8 0

Answer:

you're a strong person so keep on keeping on.

Explanation:

Grace [21]3 years ago
7 0

Answer:

I hope you get better and stay positive also please stay safe

Explanation:

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Sugar dissolving in warm water is chemical or phyiscal change
BlackZzzverrR [31]
Hey there! Great question;) Answer:Physical change Explanation: When sugar mixes with water, at the end, the chemical formulas are the same. Nothing has changed! I hope this helps;)
5 0
3 years ago
I am a celestial body that does not produce light. I orbit a planet
Artyom0805 [142]
A moon would be the correct answer.
5 0
3 years ago
How many grams are in 0.35 moles of C2H4? please show dimensional analysis
fredd [130]

Answer:

9.8g

Explanation:

Using periodic table find molar mass of C and H:

C=12.01g/mol

H=1.008g/mol

Molar mass of C2H4=(12.01)2+(1.008)4=28.03g/mol

Using molar mass times moles of the chemical to find the mass in 0.35 moles of c2h4:

28.03 x 0.35=9.8grams

5 0
3 years ago
For an alloy containing 50% cu and 50% ni, calculate the amounts of solid s and liquid l presents at 1300c. show that the total
iris [78.8K]
100 %cuni calculate the amounts of solid s and liquid
3 0
3 years ago
A 25.0 ml sample of 0.150 m butanoic acid is titrated with a 0.150 m naoh solution. what is the ph after 26.0 ml of base is adde
lesantik [10]
First,
Moles of HBu = Volume per liter * moles of HBu/ liter
                        =  25ml/1000 * 0.15 = 0.00375 moles
moles of NaOH = volume per liter * moles of NaOH/liter
                           = 1 ml/1000 * 0.15 =  0.00015 moles
according to this equation:
HBu + NaOH → H2O + NaBu
when 1 mol of NaOH gives 1mol of HBu
So     0.00015 of NaOH will give 0.00015 mol of HBu 
∴moles of HBu which remains =   0.00375- 0.00015 = 0.0036 moles 

∴moles of Bu- produced = 0.00015 moles
when the total volume = 0.025 + 0.026 =0.051 L
[HBu] = 0.0036moles / 0.051 L = 0.071 moles
[Bu] = 0.00015 / 0.051L = 0.0029 moles
when Ka = [H+] [Bu] / [HBu]
1.5x10^-5 = [H+] (0.0029) /(0.071)
∴[H+] =1x10^-6 / 0.076 = 1.5 x 10^-5
∴PH = -㏒[H+]
        = - ㏒ 1.5x10^-5 
        = 4.81

3 0
3 years ago
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