Answer is: 162 g of beryllium.
Chemical reaction: Be + 2H₂O → Be(OH)₂ + H₂.
m(H₂) = 36,0 g.
m(Be) = ?
n(H₂) = m(H₂) ÷ M(H₂)
n(H₂) = 36,0 g ÷ 2 g/mol = 18 mol.
from reaction: n(Be) : n(H₂) = 1 : 1.
n(Be) = n(H₂) = 18 mol.
m(Be) = n(Be) · M(Be).
n(Be) = 18 mol · 9 g/mol = 162 g.
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Answer:
Do you have options of answers for this question
Answer:
0.16 atm
Explanation:
Let's look at the formula PV=nRT. First of all, T should be in kelvin, so let's add 273. Now solve for P so we get P = nRT/V.
Now let's plug these in...
P = (0.034 mol)(0.08206 L atm mol^-1 K^-1)(298 K)/5.1 L
After solving and rounding to sig figs we get 0.16 atm
Answer:
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Explanation:
