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tia_tia [17]
3 years ago
15

How many molecules of N204 are in 85.0 g of N2O4?

Chemistry
1 answer:
alukav5142 [94]3 years ago
4 0

Answer:

5.56 × 10^23 molecules

Explanation:

The number of molecules in a molecule can be calculated by multiplying the number of moles in that molecule by Avagadro's number (6.02 × 10^23)

Using mole = mass/molar mass

Molar mass of N2O4 = 14(2) + 16(4)

= 28 + 64

= 92g/mol

mole = 85.0/92

= 0.9239

= 0.924mol

number of molecules of N2O4 (nA) = 0.924 × 6.02 × 10^23

= 5.56 × 10^23 molecules

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Give the ideal bond angle for BrO3- ion? I know this has trigonal bipyramidal geometry and therefore the bond angle is < 109.
Vadim26 [7]

Now that we have a background in the Lewis electron dot structure we can use it to locate the the valence electrons of the center atom. The valence-shell electron-pair repulsion (VSEPR) theory states that electron pairs repel each other whether or not they are in bond pairs or in lone pairs. Thus, electron pairs will spread themselves as far from each other as possible to minimize repulsion. VSEPR focuses not only on electron pairs, but it also focus on electron groups as a whole. An electron group can be an electron pair, a lone pair, a single unpaired electron, a double bond or a triple bond on the center atom. Using the VSEPR theory, the electron bond pairs and lone pairs on the center atom will help us predict the shape of a molecule.

The shape of a molecule is determined by the location of the nuclei and its electrons. The electrons and the nuclei settle into positions that minimize repulsion and maximize attraction. Thus, the molecule's shape reflects its equilibrium state in which it has the lowest possible energy in the system. Although VSEPR theory predicts the distribution of the electrons, we have to take in consideration of the actual determinant of the molecular shape. We separate this into two categories, the electron-group geometry and the molecular geometry.

6 0
3 years ago
Ex1. how many moles correspond to 250 g of each of the following compounds?
Ivahew [28]

Answer:

Ex1 = 4.3 moles

Explanation:

for Ex 1

 ** Number of mole = Mass (g) / Molecular weight ' Mw'  (g/mole)

for a = NaCl , first you must be calculate Mw = look to periodic table

Atomic weight for Na is 22.9 = 23 g and for Cl is 35.45 = 35 g

so Mw for NaCl = 23+35 = 58 g/mole

so Number of Moles for NaCl 250 g is

Number of Moles = 250 / 58 = 4.3 moles

do same for others ...

good luck ..

3 0
3 years ago
Read 2 more answers
Calculate the volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.
gtnhenbr [62]

535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given:

C(s) + O_2(g) ⇒CO_2(g)

1 mole of CO_2(g) is formed from 1 mole of charcoal, that means 1 mole of CO_2(g) is formed from 12 g of charcoal.

1 lbs = 453.592 grams

6.75 lbs = 6.75 x 453.592 =3061.746g

So, CO_2(g) formed from 3061.746g of charcoal is:

=\frac{1}{12} x 3061.746g

=255.14 mol.

Now, at STP, the volume of 1 mol of gas =22.4 L

Volume of 255.14 mol of CO_2(g) = 255.14 x 22.4 L

Volume of 255.14 mol of CO_2(g) = 535.8 L

Hence, 535.8 L volume(in L), at STP, of carbon dioxide produced by the complete combustion of 6.75 lbs of charcoal.

Learn more about the ideal gas here:

brainly.com/question/27691721

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3 0
2 years ago
A student jumps of a sled toward the west after it stops at the bottom of an icy hill. Based on the law of action-reaction, in w
Delicious77 [7]

Answer:

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Explanation:

Given Newton's third law of motion; "Action and reaction are equal and opposite", when a student jumps off a sled toward the west after it stops at the bottom of an icy hill, the sled will move in the East direction.

This is because, the force exerted on the sled is a reaction force and is opposite in direction to the force that thrusts the boy westward though equal in magnitude with the former.

3 0
3 years ago
Answer all with detail please! Easy for those who have completed chemistry courses!
Zina [86]

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c) CH4

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d)CH2O

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5 0
3 years ago
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