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maks197457 [2]
3 years ago
7

What is the molarity of a solution that contains 1.1 moles of lithium in 0.5 liters of solution?

Chemistry
2 answers:
cluponka [151]3 years ago
8 0
0.5 litres contain 1.1 moles
therefore 1 litre will have= 1*1.1/0.5
             molarity=2.2M
dimulka [17.4K]3 years ago
8 0

Answer:

The correct answer is 2.2 mol/L

Explanation:

Molarity of a solution is used to determine the concentration of that solution. It is mathematically expressed as

Molarity (M) = number of moles ÷ volume (in liters or dm³)

The unit for molarity is mol/L or mol/dm³ or M

From the question, number of moles is <u>1.1 moles</u> and the volume is <u>0.5 liters</u>.

Hence,

Molarity = 1.1 ÷ 0.5

Molarity = 2.2 mol/L

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What is the classification of a solution of naoh with a ph of 8.3?
Maksim231197 [3]

Answer:

  • <u>Alkaline or basic solution </u>(alkaline and basic means the same)

Explanation:

According to the <em>pH</em>,  solutions may be classified as neutral, acidic, or alkaline (basic).

This table shows such classification:

pH               classification

  7                   neutral

> 7                   alkaline or basic

< 7                   acidic

Thus, since the pH of the solution is 8.3, which is greater than 7, the solution is classified as basic (alkaline).

Additionally, you must learn that pH is a logarithmic scale for the concentration of hydronium ions in the solution.

  • pH = - log [H₃O⁺]

You can calculate the concentration of hydronium ions using antilogarithm properties:

pH=-log[H_3O^+]\\ \\ {[H_3O^+]}=10^{-pH}\\ \\ {[H_3O^+]}=10^{-8.3}=0.00000000501

NaOH solutions are alkaline solutions, bases, according to Arrhenius model,  because they contain OH⁻ ions and release them when ionize in water.

8 0
3 years ago
A mileage test is conducted for a new car model. Thirty randomly selected cars are driven for a month and the mileage is measure
Leni [432]

Answer:  (27.81,\ 29.39)

Explanation:

Given : Sample size : n= 30 , it means it is a large sample (n≥ 30), so we use z-test .

Significance level : \alpha: 1-0.95=0.05

Critical value: z_{\alpha/2}=1.96

Sample mean : \overline{x}=28.6

Standard deviation : \sigma=2.2

The formula to find the confidence interval is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 28.6\pm (1.96)\dfrac{2.2}{\sqrt{30}}

i.e. 28.6\pm 0.787259889321

\approx28.6\pm 0.79=(28.6-0.79,28.6+0.79)=(27.81,\ 29.39)

Hence, the 95% confidence interval for the mean mpg in the entire population of that car model = (27.81,\ 29.39)

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What is the median of the following set: 2, 4, 6, 8, and 10?
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Answer:9

Explanation:

(3+8+10+15)/4 = 36/4 = 9

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What is GMOs? ( Thanks btw )​
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