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maks197457 [2]
3 years ago
7

What is the molarity of a solution that contains 1.1 moles of lithium in 0.5 liters of solution?

Chemistry
2 answers:
cluponka [151]3 years ago
8 0
0.5 litres contain 1.1 moles
therefore 1 litre will have= 1*1.1/0.5
             molarity=2.2M
dimulka [17.4K]3 years ago
8 0

Answer:

The correct answer is 2.2 mol/L

Explanation:

Molarity of a solution is used to determine the concentration of that solution. It is mathematically expressed as

Molarity (M) = number of moles ÷ volume (in liters or dm³)

The unit for molarity is mol/L or mol/dm³ or M

From the question, number of moles is <u>1.1 moles</u> and the volume is <u>0.5 liters</u>.

Hence,

Molarity = 1.1 ÷ 0.5

Molarity = 2.2 mol/L

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Which could describe the motion of an object? Select 3 correct answers. distance = 10 meters and displacement = 1 meter distance
Anit [1.1K]

Answer:

The three correct statements which could describe the motion of an object are:

<u><em /></u>

  • <u><em>distance = 10 meters and displacement = 1 meter </em></u>
  • <u><em>distance = 10 meters and displacement = 0 </em></u>
  • <u><em>distance = 10 meters and displacement = 10 meters</em></u>

Explanation:

<em>Motion</em> is the change of position of an object along any path. As such, the path can be rectilinear or along a curve whose direction is variable.

Two important characteristics used to describe a motion are the length of the path traveled and the final distance from the starting point.

The length of the path traveled is what distance describes. The final distance from the starting point to the final point is what displacement describes.

The maginitude of the displacement is the difference between the final position and the starting position.

When the path traveled is rectilinear, the distance and the magnitude of the displacement are the same.

When the path is not rectilinear, the distance (the length of the path) is always greater than the magnitude of the displacement.

Thus, as for the correct statements, you have:

  • <u>distance = 10 meters and displacement = 1 meter </u>

        This means that the object traveled along a 10 meters path, but since it was not rectilinear, the difference between the final position and the starting position is just 1 meter.

  • <u>distance = 10 meters and displacement = 0 </u>

<u />

       This means that the object traveled 10 meters but it ended back in the very same place from which it departed (a complete turn around a table, for example).

  • <u>distance = 10 meters and displacement = 10 meters</u>

        This means that the travel was in the trip was alogn a straight line, and the object traveled 10 meters and ended 10 meters away from the starting place.

As for the two incorrect statements:

  • <u>distance = 0 and displacement = 10 meters </u>

  • <u>distance = 1 meter and displacement = 10 meters</u>

It is not possible that the object ended up 10 meters away from where it was (the displacement), by traveling just 1 meter less than that.

8 0
3 years ago
Read 2 more answers
If velocity is positive, which would most likely yield a negative acceleration?
Viktor [21]

Answer: An initial velocity

Explanation:

5 0
4 years ago
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Help sdfghrthfbfdve aahhhhhhhh
nirvana33 [79]
I believe the answer is C !
5 0
3 years ago
What type of pressure would you expect to find at the equator?
vesna_86 [32]
Answer: low pressure

Explanation: Air at the equator is warmer and the air above expands, becomes less dense and rises
6 0
3 years ago
The radioisotope phosphorus-32 is used in tracers for measuring phosphorus uptake by plants. The half-life of phosphorus-32 is 1
Harman [31]

Answer:

54 days

Explanation:

We have to use the formula;

0.693/t1/2 =2.303/t log Ao/A

Where;

t1/2= half-life of phosphorus-32= 14.3 days

t= time taken for the activity to fall to 7.34% of its original value

Ao=initial activity of phosphorus-32

A= activity of phosphorus-32 after a time t

Note that;

A=0.0734Ao (the activity of the sample decreased to 7.34% of the activity of the original sample)

Substituting values;

0.693/14.3 = 2.303/t log Ao/0.0734Ao

0.693/14.3 = 2.303/t log 1/0.0734

0.693/14.3 = 2.6/t

0.048=2.6/t

t= 2.6/0.048

t= 54 days

3 0
3 years ago
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