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olga nikolaevna [1]
3 years ago
9

Write a conclusion using the CER method. Your conclusion must include the following: - Claim: State your claim. Your claim is th

e answer to the original question: “What is the difference between a physical and a chemical change?” - Evidence & Reasoning: Provide evidence and reasoning to back up your claim. To do this, you need to discuss at least one example of a physical change and one example of a chemical change from the card sort. Using specific evidence and the definition of a physical/chemical change, describe how you knew what type of change had occurred.
Chemistry
1 answer:
Karolina [17]3 years ago
4 0
Nobody on here is going to write a entire cer for you
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____N2 + ____H2  ____NH3
Fiesta28 [93]

Answer:

N2 + 3H2 + 2NH3

Explanation:

I'm assuming you're balancing the chemical equation

3 0
2 years ago
Read 2 more answers
Chemical formula for sodium and sulfur
Nookie1986 [14]
The chemical formula for sodium and sulfur is Na2S I believe...
8 0
2 years ago
Give two examples of electrical energy being transformed in to another type of energy.Tell what energy is produced
seraphim [82]

Answer:

1.Electric generators (mechanical energy to electricity)

2.Windmills (mechanical energy to electricity)

7 0
2 years ago
How many grams of nickel(II) chloride do you need to precipitate 503 mg of silver chloride in the reaction between nickel(II) ch
maxonik [38]

From the information provided in the question, the mass of NiCl2 required is 0.23 g.

NiCl2(aq) + 2AgNO3(aq) -------> 2AgCl(s) + Ni(NO3)2(aq)

Number of moles of AgCl= Mass/molar mass

Molar mass of AgCl= 143 g/mol

Substituting values;

Number of moles = 503 × 10^-3g/143 g/mol= 0.00352 moles

Since 1 mole NiCl2 precipitates 2 moles of AgCl

x moles of NiCl2 precipitates  0.00352 moles of AgCl

x = 1 mole ×  0.00352 moles/2 moles

x = 0.00176 moles of NiCl2

Mass of NiCl2= 0.00176 moles × 130 g/mol = 0.23 g

Learn more: brainly.com/question/2510654

5 0
2 years ago
An aqueous solution of an unknown quantity of a nonelectrolyte solute is found to have a freezing point of −0.58°c.what is the m
adell [148]
Depression in freezing point is a colligative property i.e. it depends upon under  of solute particles present in solution.

Depression in freezing point (ΔTf) is mathematically expressed as,
ΔTf = Kf X m        ............... (1)
where Kf = cryoscopic constant
m = molality of solution

If solvent used is water, Kf = 1.853 K Kg/mol and Freezing point of pure solvent = 0 oC
∴ΔTf = 0.58 K         ............... (2)
Substituting 2 in 1 we get
0.58 = 1.853 X m
∴ m = 0.313 m

Thus, molality of solution is 0.313 m

4 0
3 years ago
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