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3 years ago

Write a balanced equilibrium equation for the dissolution of nai in water. include phases.

Chemistry

2 answers:

Lorico [155]3 years ago

4 0

Explanation:

The compound sodium iodide (NaI) is an ionic compound as there is formation of chemical bond by transfer of electrons from sodium to iodine.

Therefore, it is a polar molecule and we know that water is also a polar solvent. Hence, like dissolves like as a result, sodium iodide will dissociate into water.

The reaction equation will be as follows.

$NaI(s) + H_{2}O \rightarrow Na^{+}(aq) + I^{-}(aq)$

Bess [88]3 years ago

3 0

Dissolution means to make the compound apart, So when we have ionic compounds like NaI which has metal and non-metal ions, It separates into parts of positive ions and negative ions. After we separate this compound apart we will put the charge of each on above its symbol and then start to balance the equation of the dissolution.

So the dissolution equation of NaI is:
NaI(s) → Na^+(s) + I^-(Aqu)

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Explanation:

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$1.634\times 10^{-18}J=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{\lambda}\\\\\lambda=12.16\times 10^{-8}m$

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Read 2 more answers