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andrew-mc [135]
3 years ago
14

The 3rd bright fringe of a double slit interference pattern is 30.0 cm above the central bright fringe. If the angle from the ho

rizontal to this 3rd bright fringe is 12.0 degrees, what is the distance (in meters) between the double slits and the viewing screen
Physics
1 answer:
Anastasy [175]3 years ago
5 0

Answer:

Explanation:

12 degree = (π / 180) x 12 radian

= .2093 radian

position of third bright fringe = 3λ D/ d where λ is wave length of light , D is screen distance and d is slit separation

given

3λ D/ d = 30 x 10⁻²

angular separation

3λ / d = .2093

from the two equation

.2093 D= 30 x 10⁻²

D = 30 x 10⁻² / .2093

= 1.43 m

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A military base a few miles from a medium- sized city is being decommissioned. The base is a large one, sited along a coastline,
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Answer:

The lack of jobs and lack of transportation to jobs

Explanation:

As it is seen, the establishment of the camping and hiking areas will dispatch buildings which were hospitals, shops and schools.

These buildings and facilities previously employed a number of workers and their removal hence, will reduce the number of available jobs.

Also, the new constructions will prove difficult in switching from one job to another.

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4 years ago
A 1.5 kg ball is dropped from a height of 2.Gm. Assuming energy is
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Answer:

Plug in the given values and solve for the final velocity. Remember, when the ball is on the ground it has a height of zero.

Explanation:

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2 years ago
1. When human bones are brittle due to eating too much dairy food, what is this called?
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Answer:

1. Osteoporosis

2. Dehydration

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6 0
3 years ago
A crate with a mass of 175.5 kg is suspended from the end of a uniform boom with a mass of 94.7 kg. The upper end of the boom is
Rudiy27

The tension in the cable is equal to 323.5 N.

<h3>What is the tension in the cable?</h3>

The tension, T in the cable is determined by taking moments about the pivot  marked X.

The angles of the boom and the cable with the horizontal are first calculated.

Angle of the boom with horizontal, θ = tan⁻¹(5/10) = 26.56°

The angle of cable with horizontal, B = tan⁻¹(4/10) = 21.80

Taking moments about the pivot:

175.5 * cos 26.56 + 94.7 * cos 26.56 * 0.5 = T (sin(26.56 + 21.80) * 1

Tension = 241.68/0.747

Tension = 323.5 N

In conclusion, the tension in the cable helps to suspend the crate.

Learn more about tension at: brainly.com/question/24994188

#SPJ1

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2 years ago
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4 years ago
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