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Savatey [412]
3 years ago
9

If the voltage in a circuit is 24 V and the current is 2 A, what is the total power in the circuit?

Physics
2 answers:
Drupady [299]3 years ago
5 0
Maybe you can divide the volts its twelve if you do that but itll show you how much to double it by

Marysya12 [62]3 years ago
3 0

V = Voltage in the circuit = 24 Volts

i = Current flowing in the circuit = 2 A

P = Total power dissipated in the circuit.

Total Power dissipated in a current carrying circuit is given as

P = i V

inserting the above values of the current and voltage in the above equation , we get

P = (2 A) (24 V)

P = (2 x 24) (AV)

P = 48 Watt                 (Since Ampere -Volt  = watt)

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torisob [31]

Answer: lots of them

Explanation:

7 0
2 years ago
A charge Q is distributed uniformly on a non-conducting ring of radius R and mass M. The ring is dropped from rest from a height
mihalych1998 [28]

Answer:

Check below for the explanation

Explanation:

Since it is stated that the ring is dropped from a height, h, through a non uniform magnetic field, two kinds of force will act on the ring, namely:

  • A magnetic force (that is non uniform since the field is  non uniform)
  • Gravitational force

A certain amount of torque is provided by the non uniform magnetic force on the ring while the force gravity pulls it down. Due to the downward pull by the force of gravity on the ring and the torque acting on it as a result of the non uniform magnetic force, the ring begins to rotate.

5 0
3 years ago
A water tank is in the shape of an inverted cone with depth 10 meters, and top radius 8 meters. Water is flowing into the tank a
Elis [28]

Answer:

The value of leaking rate in the question is repeated. By searching on the web I could find the correct value wich is 0.002h^2 m^3 /min.

The depth of the water has to be equal to 7.07 m in order to have a stationary volume.

Explanation:

In order to have a stationary water level the flow of water that comes into the tank (0.1 m^3/min) must be equal to the flow of water that goes out of the tank (0.002*h^2 m^3/min), therefore:

0.002*h^2 = 0.1

h^2 = 0.1/0.002

h^2 = 50

h = sqrt(50) = 7.07 m

7 0
3 years ago
Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0 °C for the following reacti
Yakvenalex [24]

The equilibrium constant of the reaction at 25⁰c will be 426827.5.

<u />

  • <u>Theory-</u>

<u>Equilibrium constant</u> :The equilibrium constant comes from the chemical equilibrium law. For the chemical equilibrium state, at a fixed constant temperature, the ratio of the product of the reaction's multiplication to the concentration of its reactants' multiplication, and each is raised to the power to the corresponding coefficients of the elements in the reaction.

The chemical equilibrium is given by for a general chemical reaction.

a. A+ b. B ⇌ c. C+ d. D,.

Kc =[C]c [D]d/[A]a [B]b.

<u>Gibb's free energy</u> :The second law of thermodynamics can be arranged in such a way that it gives a new expression when a chemical reaction happens at a constant temperature and constant pressure.

G=H-TS

  • <u>Calculations</u>:-

T=25⁰c

G=51.4 x 10³J

\\\\k=GR+\frac{nRT}{Z} \\

k= equilibrium constant ,G=Gibbs free energy ,n= no. of moles ,R=Gas constant ,T=temperature ,Z=compressibility

Ideal.Situation=\left \{ {{Z=1} \atop {n=1}} \right.

\\\\\\k=GR+RT

k=51.4 x 10³ x 8.3 + 8.3 x 25

k=426827.5

To learn equilibrium constant-

<u>brainly.com/question/19669218</u>

#SPJ4

6 0
1 year ago
numerical question : what is the required heat to raise the temperature of 2 kg parrafin by 10 Celsius if 44000 joules is requir
kirill115 [55]

Answer:

The heat energy required is, E = 2200 J

Explanation:

Given,

The mass of paraffin, m = 2 Kg

The energy required to raise the temperature of the paraffin by 200° C = 44000 J

Then the heat energy required to raise the temperature of the paraffin by 10° C is given by,

Since 44000 J raises temperature by 200° C, then

                              E = 44000 J / 20

                                 = 2200 J

Hence, the energy required to raise the temperature of the paraffin by 10° C is, E = 2200 J

8 0
3 years ago
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