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Nikitich [7]
3 years ago
14

Fill In the Blank: In a physical change, the of a substance does not change. The only thing that changes is a .

Physics
1 answer:
zubka84 [21]3 years ago
4 0
In a physical change, the [chemical identity] of a substance does not change. The only thing that changes is the [state of the matter]
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A drag racing vehicle travels from 0 to 100mph north in 5 seconds. What is the acceleration
kap26 [50]

The acceleration of the car is 8.9 m/s^2

Explanation:

The acceleration of an object is given by

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time elapsed

Here we have to convert the initial and final velocity of the vehicle into SI units. So we have:

u = 0 is the initial velocity

v=100 mph \cdot \frac{1609 m/mi}{3600 s/h}=44.7 m/s is the final velocity

t = 5 s is the time elapsed

Solving for a, we find the acceleration:

a=\frac{44.7-0}{5}=8.9 m/s^2

Learn more about acceleration:

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5 0
4 years ago
A traveling wave has displacement given by y(x,t)=(2.0cm)×cos(2πx−4πt), where x is measured in cm and t in s. what is the speed
quester [9]

Answer:

v = 2 cm/s

Explanation:

The equation of the wave is

y(x,t)   =  (2.0cm)*cos(2π*x−4π*t)

Where,

x is measured in cm

t in s

A more general formula for this equation would be

y(x,t)   =  A*cos(k*x−ω*t)

Where,

A = amplitude.

k = the wavenumber

ω = the angular frequency

The velocity of the wave corresponds to

v = ω/k

v = 4π / 2π = 2 cm/s

v = 2 cm/s

8 0
3 years ago
As a wave travels through a medium, it displaces particles in a direction parallel to the motion of the wave. We can conclude th
IgorLugansk [536]
Im sure the answer to this question is c. 
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3 years ago
The power of a motorcycle is 150W and the time is 14s. What is the work?
Artyom0805 [142]
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3 years ago
A popular ride at some playgrounds consists of two circular disks joined by rungs . The center of the unit is attached to a hori
weeeeeb [17]

Answer:

v = 36.667 m/s

Explanation:

Knowing the rotational inertia as

Lₙ = 550 kg * m²

r = 1.0 m

m = 30.0 kg

To determine the minimum speed v must have when she grabs the bottom

Lₙ =  I * ω

I = ¹/₂ * m * r²

I = ¹/₂ * 30.0 kg * 1.0² m

I = 15 kg * m²

Lₙ =  I * ω  ⇒ ω =  Lₙ / I

ω = [ 550 kg * m² /s  ] / ( 15 kg * m² )

ω = 36.667 rad /s

v = ω * r

v = 36.667 m/s

7 0
4 years ago
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