Answer:
v = 2 cm/s
Explanation:
The equation of the wave is
y(x,t) = (2.0cm)*cos(2π*x−4π*t)
Where,
x is measured in cm
t in s
A more general formula for this equation would be
y(x,t) = A*cos(k*x−ω*t)
Where,
A = amplitude.
k = the wavenumber
ω = the angular frequency
The velocity of the wave corresponds to
v = ω/k
v = 4π / 2π = 2 cm/s
v = 2 cm/s
10.7 or round it up to 11
Answer:
v = 36.667 m/s
Explanation:
Knowing the rotational inertia as
Lₙ = 550 kg * m²
r = 1.0 m
m = 30.0 kg
To determine the minimum speed v must have when she grabs the bottom
Lₙ = I * ω
I = ¹/₂ * m * r²
I = ¹/₂ * 30.0 kg * 1.0² m
I = 15 kg * m²
Lₙ = I * ω ⇒ ω = Lₙ / I
ω = [ 550 kg * m² /s ] / ( 15 kg * m² )
ω = 36.667 rad /s
v = ω * r
v = 36.667 m/s