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umka21 [38]
3 years ago
8

Assign the oxidation number for (NH4)3PO4

Chemistry
2 answers:
navik [9.2K]3 years ago
6 0
N(-3)
N(+1)
P(+5)
O(-2)

-3*3+(+1)*12+(+5)+(-2)*4=-9+12+5-8 =0 -the sum of oxidation number in the molecule should be equal zero.

baherus [9]3 years ago
3 0

Explanation:

Hello!

Let's solve this!

In a salt, we must take into account that the sum of the oxidation numbers is equal to zero since the molecule is stable.

In this case the molecule is a salt and is (NH4) 3PO4

N = -3

H = + 1 (there are four atoms in total is +4)

(NH4) 3 = (- 3 + 4) * 3 = + 3

P = + 5

O = -2 (since there are 4 atoms in total it is -8)

PO4 = + 5-8 = -3

The total is: -3 + 3 = 0

We verify that the charges give a total of zero, so that our calculation is well done.

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5 0
3 years ago
What mass percent solution will result from dissolving 0.126 moles of AgNO3 in 475 g. of water
Kruka [31]

Answer:

The answer to your question is: 4.5 %

Explanation:

0.126 moles of AgNO3

mass percent = ?

mass of water = 475 g

Formula

               weight percent = weight of solute / weight of solution x 100

Weight of solute

 MW AgNO3 = 108 + 14 + (16 x 3)

                      = 108 + 14 + 48

                     = 170 g

                        170 g of AgNO3 -------------------  1 mol

                        x                         ---------------------  0.126 moles

                        x = (0.126 x 170) / 1  = 21.42 g of AgNO3

Weight percent = 21.42/475 x 100

                          = 4.5 %

7 0
3 years ago
A sample of gas contains 0.1100 mol of HBr(g) and 5.00x10^-2 mol of Cl2(g) and occupies a volume of 5.85 L. The following reacti
Vesna [10]

The volume of the sample after the reaction : V₂=5.484 L

<h3>Further explanation</h3>

Given

Reaction

2HBr(g) + Cl2(g) => 2HCl (g)+Br2(g)

0.1100 mol of HBr(g)

5x10⁻² mol of Cl2(g)

Required

The volume of the sample after reaction

Solution

Find limiting reactant :

0.11/2 : 0.05/1 = 0.055 : 0.05

Limiting reactant : Cl₂

mol Products based on mol Cl₂

mol products = mol HCl + mol Br₂

mol products = 2/1x0.05 + 1/1x0.05

mol products = 3 x 0.05 = 0.15

mol reactants = 0.11 + 0.05 = 0.16

<em>From Avogadro's law, </em>

In the same T, P, and V, the gas contains the same number of molecules  

So the ratio of gas volume will be equal to the ratio of gas moles  

 V₁/n₁=V₂/n₂

1 = reactants, 2 = products

Input the value :

5.85/0.16=V₂/0.15

V₂=5.484 L

6 0
3 years ago
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