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Sonja [21]
3 years ago
11

What mass of mgf2 is contained in 80.85 g of a 22.4% by mass solution of mgf2 in water?

Chemistry
2 answers:
Aleks [24]3 years ago
4 0
Formula: % by mass = (mass of solute / mass of solution] *100

Data:

mass of solution = 80.85 g

% by mass = 22.4%

Unknown = mass of solute

Solution

% by mass = (mass of solute / mass of solution] *100 = >

mass of solute = % by mass * mass of solution / 100

mass of solute = 22.4 * 80.85 / 100 = 18.11 g

Answer: 18.11 g
atroni [7]3 years ago
4 0

Answer : The mass of MgF_2 contained is, 18.1104 grams

Solution : Given,

Given mass of solution = 80.85 g

22.4% by mass solution of MgF_2 means that 22.4 grams of MgF_2 present in 100 gram of solution.

As, 100 grams of solution contains 22.4 grams of MgF_2

So, 80.85 grams of solution contains \frac{22.4}{100}\times 80.85=18.1104 grams of MgF_2

Therefore, the mass of MgF_2 contained is, 18.1104 grams

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A gas is contained in a cylinder with a volume of 2.9 L at a temperature of 32.7oC and a pressure of 645.3 torr. The gas is then
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Pressure P1 = 645.3 torr

New Volume V2 = 0.23 L

New temperature T2 = 894.7°C

Convert Celsius to Kelvin

(894.7°C + 273 = 1167.7K)

New pressure = ?

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Since 760 torr = 1 atm

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760 torr x Z = 31079.045 torr x 1 atm

Z = 31079.045 torr / 760 torr

Z = 40.89 atm (Round to the nearest whole number as 41 atm)

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