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Sonja [21]
3 years ago
11

What mass of mgf2 is contained in 80.85 g of a 22.4% by mass solution of mgf2 in water?

Chemistry
2 answers:
Aleks [24]3 years ago
4 0
Formula: % by mass = (mass of solute / mass of solution] *100

Data:

mass of solution = 80.85 g

% by mass = 22.4%

Unknown = mass of solute

Solution

% by mass = (mass of solute / mass of solution] *100 = >

mass of solute = % by mass * mass of solution / 100

mass of solute = 22.4 * 80.85 / 100 = 18.11 g

Answer: 18.11 g
atroni [7]3 years ago
4 0

Answer : The mass of MgF_2 contained is, 18.1104 grams

Solution : Given,

Given mass of solution = 80.85 g

22.4% by mass solution of MgF_2 means that 22.4 grams of MgF_2 present in 100 gram of solution.

As, 100 grams of solution contains 22.4 grams of MgF_2

So, 80.85 grams of solution contains \frac{22.4}{100}\times 80.85=18.1104 grams of MgF_2

Therefore, the mass of MgF_2 contained is, 18.1104 grams

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dolphi86 [110]

Answer:

3.824 atm

Explanation:

From the ideal gas equation

P = mRT/MW × V

m is mass of testosterone = 12.9 g

R is gas constant = 82.057 cm^3.atm/mol.K

T is temperature of benzene solution = 298 K

MW is molecular weight of testosterone = 288.40 g/mol

V is volume of benzene solution = 286 ml = 286 cm^3

P = 12.9×82.057×298/288.4×286 = 3.824 atm

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2 years ago
The three isomers of pentane have different
8_murik_8 [283]
The three isomers of pentane have different structural formulas.
8 0
3 years ago
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Ammonium phosphate is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid with ammonia . Wha
Dmitry [639]

Answer:

7.5 g

Explanation:

There is some info missing. I think this is the original question.

<em>Ammonium phosphate ((NH₄)₃PO₄) is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid (H₃PO₄) with ammonia (NH₃). What mass of ammonium phosphate is produced by the reaction of 4.9 g of phosphoric acid? Be sure your answer has the correct number of significant digits.</em>

<em />

Step 1: Write the balanced equation

H₃PO₄ + 3 NH₃ ⇒ (NH₄)₃PO₄

Step 2: Calculate the moles corresponding to 4.9 g of phosphoric acid

The molar mass of phosphoric acid is 98.00 g/mol.

4.9 g \times \frac{1mol}{98.00g} = 0.050mol

Step 3: Calculate the moles of ammonium phosphate produced from 0.050 moles of phosphoric acid

The molar ratio of H₃PO₄ to (NH₄)₃PO₄ is 1:1. The moles of (NH₄)₃PO₄ produced are 1/1 × 0.050 mol = 0.050 mol.

Step 4: Calculate the mass corresponding to 0.050 moles of ammonium phosphate

The molar mass of ammonium phosphate is 149.09 g/mol.

0.050mol \times \frac{149.09 g}{mol} = 7.5 g

6 0
2 years ago
Consider a balloon with volume V. It contains n moles of gas and has an internal pressure of P. The temperature of the gas is T.
Maksim231197 [3]

Answer:

V₂ = 0.6 V.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n is constant, and have different values of P, V and T:

<em>(P₁V₁T₂) = (P₂V₂T₁).</em>

<em></em>

V₁ = V, P₁ = P, T₁ = T.

V₂ = ??? V, ​P₂ = 1.25 P, T₂ = 0.75 T.

<em>∴ V₂ = (P₁V₁T₂)/(P₂T₁) =</em> (P)(V)(0.75 T)/(1.25 P)(T)<em> = 0.6 V.</em>

3 0
3 years ago
Read 2 more answers
List emergency equipment, those are available in the laboratory?
mestny [16]

Answer:

Hands-free eyewash stations, sand bucket, fire blankets, fire extinguishers, fire alarm system and first aid kit.

Explanation:

Working in laboratories has many risks, therefore, preventive measures that should be incorporated to avoid the occurrence of any laboratory accidents.

Some of the important emergency equipment that should be available in laboratories are: hands-free eyewash stations, sand bucket, fire blankets, fire extinguishers, fire alarm system, chemical storage cabinet, first aid kits and fume hood.

Some of the personal protective equipment include lab coats, goggles, safety gloves and face shield.

7 0
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