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Sonja [21]
3 years ago
11

What mass of mgf2 is contained in 80.85 g of a 22.4% by mass solution of mgf2 in water?

Chemistry
2 answers:
Aleks [24]3 years ago
4 0
Formula: % by mass = (mass of solute / mass of solution] *100

Data:

mass of solution = 80.85 g

% by mass = 22.4%

Unknown = mass of solute

Solution

% by mass = (mass of solute / mass of solution] *100 = >

mass of solute = % by mass * mass of solution / 100

mass of solute = 22.4 * 80.85 / 100 = 18.11 g

Answer: 18.11 g
atroni [7]3 years ago
4 0

Answer : The mass of MgF_2 contained is, 18.1104 grams

Solution : Given,

Given mass of solution = 80.85 g

22.4% by mass solution of MgF_2 means that 22.4 grams of MgF_2 present in 100 gram of solution.

As, 100 grams of solution contains 22.4 grams of MgF_2

So, 80.85 grams of solution contains \frac{22.4}{100}\times 80.85=18.1104 grams of MgF_2

Therefore, the mass of MgF_2 contained is, 18.1104 grams

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0.114 mol/l  
The equilibrium equation will be: 
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The square factor for BrCl is due to the 2 coefficient on that side of the equation.  
Now solve for BrCl, substitute the known values and calculate. 
Kc = ([Br2][Cl2])/[BrCl]^2 
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[BrCl] = sqrt(0.013021127 mol^2/l^2) 
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Rounding to 3 significant figures gives 0.114 mol/l
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go to ptable.com. it helps a lot

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Luda [366]

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